Question

运行以下查询时，我试图获取不同的行。但是我得到重复的行当我使用SELECT DISTINCT时出现错误，并且GROUP BY是相同的，我知道这是可能的，但是我很难弄清楚

不同的记录在第一列TEST.TEST_ID

SELECT TEST.TEST_ID, TEST.TEST_TYP_ID, TEST.LOCATIONSECTIONID, TY.NAME, TEST.TITLE, TXT.TEXT, TEST.REPORT_DATE, TEST.START_DATE, TEST.END_DATE, SC.DISPLAY_NAME, EL.EL_ID, SC.SC_ID, O.DISPLAY_NAME
FROM TEST_TEST AS TEST
    LEFT JOIN TEST_TYPE TY ON TEST.TEST_TYP_ID = TY.TEST_TYP_ID
    LEFT JOIN TEST_OPTN_TEST OPT ON TEST.TEST_ID = OPT.TEST_ID
    LEFT JOIN TEST_OPTN O ON OPT.OPTION_NUMBER = O.OPTION_NUMBER
    LEFT JOIN TEST_EL EL ON OPT.EL_ID = EL.EL_ID
    LEFT JOIN TEST_TXT TXT ON TEST.TEST_ID = TXT.TEST_ID
    LEFT JOIN TEST_EL_SC SC ON OPT.EL_ID = SC.EL_ID
WHERE
TEST.TEST_TYP_ID = 1 
AND TEST.TITLE LIKE '%SOME TEXT%'
AND SC.DISPLAY_NAME = 'SOME TEXT'

谢谢

Answer 1

我知道我收到了错误无法将ntext数据类型选择为DISTINCT，因为它不可比较。（第1行）所以我删除了TXT.TEXT列，得到了不同的行

SELECT DISTINCT TEST.TEST_ID, TEST.TEST_TYP_ID, TEST.LOCATIONSECTIONID, TY.NAME, TEST.TITLE, TEST.REPORT_DATE, TEST.START_DATE, TEST.END_DATE, SC.DISPLAY_NAME, EL.EL_ID, SC.SC_ID, O.DISPLAY_NAME
FROM TEST_TEST AS TEST
    LEFT JOIN TEST_TYPE TY ON TEST.TEST_TYP_ID = TY.TEST_TYP_ID
    LEFT JOIN TEST_OPTN_TEST OPT ON TEST.TEST_ID = OPT.TEST_ID
    LEFT JOIN TEST_OPTN O ON OPT.OPTION_NUMBER = O.OPTION_NUMBER
    LEFT JOIN TEST_EL EL ON OPT.EL_ID = EL.EL_ID
    LEFT JOIN TEST_TXT TXT ON TEST.TEST_ID = TXT.TEST_ID
    LEFT JOIN TEST_EL_SC SC ON OPT.EL_ID = SC.EL_ID
WHERE
TEST.TEST_TYP_ID = 1 
AND TEST.TITLE LIKE '%SOME TEXT%'
AND SC.DISPLAY_NAME = 'SOME TEXT'

这可行，但是如果我要包含该文本列，我会这样做。

谢谢

从多个表中选择DISTINCT行，其中只有1列具有不同的记录

1 个答案: