我们有一个与acumatica 6.10一起使用的外部应用程序，现在我们正在迁移到acumatica 2017R2，该应用程序现在存在一些问题。例如，如果我在状态中使用“打开”，则会收到一个错误，但是如果我在西班牙语中使用“ Abierto”，它将起作用！那么，如果用户使用英语进行设置，为什么会发生这种情况？
using System;
using System.Linq;
using ConsoleApp3.AR302000;
using ConsoleApp3.GI000128;
using System.IO;
namespace ConsoleApp3
{
class Program
{
static void Main(string[] args)
{
// The code provided will print ‘Hello World’ to the console.
// Press Ctrl+F5 (or go to Debug > Start Without Debugging) to run your app.
AR302000.Screen src = new AR302000.Screen();
GI000128.Screen GI128scr = new GI000128.Screen();
try
{
GI128scr.Logout();
}
catch (Exception)
{
}
GI128scr.CookieContainer = new System.Net.CookieContainer();
GI000128.LoginResult lr = GI128scr.Login("user@company:SUC01", "thisisnotmtypassword");
if (lr != null && lr.Code == GI000128.ErrorCode.OK)
{
GI000128.Content GI128Content = GI128scr.GetSchema();
GI000128execute(GI128scr, GI128Content);
//AR302010method(src);
}
try
{
Console.WriteLine("Login out ....");
GI128scr.Logout();
Console.WriteLine("Desconectado");
}
catch (Exception e)
{
}
Console.ReadKey();
}
private static void GI000128execute(GI000128.Screen gI128scr, GI000128.Content gI128Content)
{
GI000128.Command[] commands = new GI000128.Command[]
{
new GI000128.Value
{
LinkedCommand = gI128Content.Filter_.BranchID,
Value = "S002"
},
new GI000128.Value
{
LinkedCommand = gI128Content.Filter_.Status,
Value = "Open"
},
new GI000128.Value
{
LinkedCommand = gI128Content.Filter_.DateFrom,
Value = "2018-10-31"
},
new GI000128.Value
{
LinkedCommand = gI128Content.Filter_.DateTo,
Value = "2018-11-01"
},
gI128Content.Result.QTOrderDate,
gI128Content.Result.QTStatus,
gI128Content.Result.BranchCD,
gI128Content.Result.QTOrderNbr,
gI128Content.Result.QTOrderType,
gI128Content.Result.QTOrderTotal,
gI128Content.Result.OwnerID
};
string[][] resultado = gI128scr.Export(commands, null, 0, true, true);
imprimir(resultado);
}
private static void imprimir(string[][] resultado)
{
int row = resultado.GetLength(0);
int column = resultado[0].GetLength(0);
for (int i = 0; i<row; i++)
{
for (int j = 0; j<column; j++)
{
Console.Write(resultado[i][j]+" | ");
}
Console.WriteLine();
}
Console.ReadKey();
}