Question

我正在寻找与JPQL中的此SQL查询等效的

SELECT l.*
FROM product_update l
    INNER JOIN (
        SELECT
            ID_PRODUCT,
            MAX(ID) AS maxID
        FROM product_update
        GROUP BY ID_PRODUCT
    ) groupel ON l.ID_PRODUCT = groupel.ID_PRODUCT
        AND l.ID = groupel.maxID
ORDER BY ID DESC

我的java类

public class ProductUpdate extends BaseEntity {

private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "PRODUCT_UPDATE_SEQUENCE")
@Column(name = "ID")
private Long id;

@JoinColumn(name = "ID_PRODUCT")
@ManyToOne()
private Product product;


@JoinColumn(name = "ID_VERSION")
@ManyToOne()
private Versioning versioning;
}

的确，一个产品可能有多个版本，但是系统仅显示具有最大（id）的产品示例：

1-Product 1 --- Version 1 
2-Product 2 --- Version 1
3-Product 3 --- Version 1
4-Product 1 --- Version 2
5-Product 3 --- Version 2
6-Product 3 --- Version 3

查询刚刚出来

2-Product 2 --- Version 1
4-Product 1 --- Version 2
6-Product 3 --- Version 3

谢谢。

Answer 1

我终于得到了很好的查询，

select pu from ProductUpdate pu where pu.id in (select MAX(pUd.id) from ProductUpdate pUd group by pUd.product.id) ORDER BY pu.id DESC.

我只是使用帖子JPA CriteriaBuilder for join in subquery来回答我。

仅在WHERE中使用JPA子查询，因此使用Netbeans警告
INNER JOIN不接受子查询。

特定的SQL到JPQL查询转换

1 个答案: