Question

我的问题是，我要获取所有3个表中都存在的数据。但是我想显示任何一个表中都没有的数据（在该项目上打印为空白或0如果它不在表的任何人中..i谷歌搜索，发现它可以通过fullouter join来完成，但是我不知道如何使用它。控制器代码：

   public function St_statement(){

        $startdate = $this->input->post('SDate');
        $enddate = $this->input->post('EDate');
        $date = str_replace('/', '-', $startdate);
        $newDate = date("Y-m-d", strtotime($date));
        $date2 = str_replace('/', '-', $enddate);
        $newDate2 = date("Y-m-d", strtotime($date2));
        $data['startdate'] = $startdate;
        $data['enddate'] = $enddate;
        if ($this->input->post('all'))
        {
        $this->db->where('billdate >=', $newDate);
        $this->db->where('billdate <=', $newDate2);
        $this->db->where('billdte >=', $newDate);
        $this->db->where('billdte <=', $newDate2);
        $this->db->select("Item");
        $this->db->select("pgroup");
        $this->db->select_sum("Stock");
        $this->db->select_sum("quantity");
        $this->db->select_sum("Qty");
        $this->db->from('opstock');
        $this->db->group_by("Item");
        $this->db->order_by("pgroup",'asc');

        $this->db->join('purchaseitem',' purchaseitem.Prdtname = opstock.Item','OUTER');
         $this->db->join('salesitem','salesitem.Prdtname =  purchaseitem.Prdtname','OUTER');
          $this->db->join('itemmaster','itemmaster.itemname =  purchaseitem.Prdtname','OUTER');
         $this->db->join('pgroup','pgroup.pgroupid = itemmaster.catcode','OUTER');

        $query = $this->db->get();
  $data['query'] = $query;

        $this->load->view('Inventory/St_Stmt', $data);
        //$this->load->view('Inventory/St_Stmt1', $data);
    }
    if($this->input->post('selected'))
    {
        if($name = $this->input->post('businessType'))
        {
        $this->db->where('billdate >=', $newDate);
        $this->db->where('billdate <=', $newDate2);
        $this->db->where('billdte >=', $newDate);
        $this->db->where('billdte <=', $newDate2);
        $this->db->where('pgroup',$name);
        $this->db->select("Item");
        $this->db->select("pgroup");
        $this->db->select_sum("Stock");
        $this->db->select_sum("quantity");
        $this->db->select_sum("Qty");
        $this->db->from('opstock');
        $this->db->group_by("Item");

        $this->db->join('purchaseitem',' purchaseitem.Prdtname = opstock.Item','OUTER');
         $this->db->join('salesitem','salesitem.Prdtname =  purchaseitem.Prdtname','OUTER');
          $this->db->join('itemmaster','itemmaster.itemname =  purchaseitem.Prdtname','OUTER');
         $this->db->join('pgroup','pgroup.pgroupid = itemmaster.catcode','OUTER');

        $query = $this->db->get();
  $data['query'] = $query;

        $this->load->view('Inventory/St_Stmt', $data);


    }

}
}

Answer 1

$ query =“ SELECT Item，pgroup，SUM（Stock）AS Stock，SUM（{quantity）AS quantity，从Qty到Qty的SUM（opstock）左联接purchaseitem上purchaseitem。Prdtname = opstock。Item 左联接salesitem上salesitem。Prdtname = purchaseitem。Prdtname 左联接itemmaster上itemmaster。itemname = purchaseitem。Prdtname 在pgroup上左联接pgroup。pgroupid = itemmaster。catcode在billdate> ='“。$ newDate。”'和{{ 1}} <='“。$ newDate2。”'AND billdate> ='“。$ newDate。”'AND billdte <='“。$ newDate2。”'GROUP BY {{1 }}按billdte ASC排序联盟选择Item，pgroup，SUM（{Item）AS pgroup，SUM（{Stock）AS Stock，SUM（quantity ）作为quantity的{{1}} 在Qty上右加入Qty。opstock = purchaseitem。purchaseitem 左联接Prdtname上opstock。Item = salesitem。salesitem 左联接Prdtname上purchaseitem。Prdtname = itemmaster。itemmaster 在itemname上左联接purchaseitem。Prdtname = pgroup。pgroup在pgroupid> ='“。$ newDate。”'和{{ 1}} <='“。$ newDate2。”'AND itemmaster> ='“。$ newDate。”'AND catcode <='“。$ newDate2。”'GROUP BY {{1 }}按billdate ASC排序选择billdate，billdte，SUM（{billdte）AS Item，SUM（{pgroup）AS Item，SUM（pgroup ）作为Stock的{{1}} 左联接Stock上quantity。quantity = Qty。Qty 在opstock上右加入purchaseitem。purchaseitem = Prdtname。opstock 左联接Item上salesitem。salesitem = Prdtname。purchaseitem 在Prdtname上左联接itemmaster。itemmaster = itemname。purchaseitem在Prdtname> ='“。$ newDate。”'和{{ 1}} <='“。$ newDate2。”'AND pgroup> ='“。$ newDate。”'AND pgroup <='“。$ newDate2。”'GROUP BY {{1 }}按pgroupid ASC排序联盟选择itemmaster，catcode，SUM（{billdate）AS billdate，SUM（{billdte）AS billdte，SUM（Item ）作为pgroup的{{1}} 左联接Item上pgroup。Stock = Stock。quantity 左联接quantity上Qty。Qty = opstock。purchaseitem 在purchaseitem上右加入Prdtname。opstock = Item。salesitem 在salesitem上左联接Prdtname。purchaseitem = Prdtname。itemmaster在itemmaster> ='“。$ newDate。”'和{{ 1}} <='“。$ newDate2。”'AND itemname> ='“。$ newDate。”'AND purchaseitem <='“。$ newDate2。”'GROUP BY {{1 }} ORDER BY Prdtname ASC”；

$ query = $ this-> db-> query（$ query）;

如何从3个表中获取数据库中的所有数据？

1 个答案: