Angular6:当网址清楚显示正确值时,为什么“ ActivatedRoute.snapshot.queryParams”为空?

时间:2018-11-15 11:01:53

标签: javascript angular ionic-framework angular6

我一页叫:

  List<string> result = list
    .Select((value, index) => new {
      value,
      index
    })
    .GroupBy(item => item.value, StringComparer.OrdinalIgnoreCase)
    .SelectMany(chunk => chunk
       .Select((item, index) => new {
          value = string.Format("{0}{1}", item.value, new string('_', index)),
          index = item.index
        }))
    .OrderBy(item => item.index)
    .Select(item => item.value)
    .ToList();

使用此网址生成正确的导航事件:

cat Cat_ kitty kittY_ dog cAt__ Dog_ monkey monKey_ Monkey__

但在目标页面中,// call this to nav to '/list' with queryParams const data = {'map-center': this.loc.join(',')}; this.router.navigate(['/list'], {queryParams:data} ); 在两种情况下都为空:

http://localhost:8100/list?map-center=13.7414025,100.51102500000002

但是,当我从浏览器重新加载时,queryParam很好。发生了什么事?

[更新] ,如果我在网址中添加参数,则queryParam可以正常工作。

// <ion-router-outlet main
//      (activate)="!!$event.viewWillEnter ? $event.viewWillEnter() : undefined"

viewWillEnter(){
    // using constructor(){ private route: ActivatedRoute }
    const mapCenter = this.route.snapshot.queryParams['map-center'];
    this.route.queryParams.subscribe(p=>console.log(">>> queryParams=", p))
}

0 个答案:

没有答案