Question

我在尝试将数字转换为单词时遇到一个问题：当我输入80时崩溃，或者如果我输入100，它会产生“一百二百”。有人可以帮我修复我的代码。

number = input("Enter a value: ")
ones = ["", "one ", "two ","three ", "four", "five ", "six ", "seven ", 
"eight ", "nine "]
teens = ["ten ", "eleven ", "twelve ", "thirteen ", "fourteen ", "fifteen ", 
"sixteen ", "seventeen ", "eighteen ", "nineteen "]
decades = ["", "twenty ", "thirty ", "forty ", "fifty ", "sixty ", "seventy 
", "eighty ", "ninety "]
hundreds = ["", "one hundred ", "two hundred ", "three hundred ", "four 
hundred ", "five hundred", "six hundred ", "seven hundred", "eight hundred", 
"nine hundred"]

word = ""
change = len(number)

while change > 0:
    if number == "0":
        word ="zero"
        break
    elif change > 1 and number[change - 2] == "1":
        for i in range(0,10):
            if number[change - 1] == str(i):
                word = teens[i] + word
    else:
        for i in range(0,10):
            if number[change - 1] == str(i):
                word = ones[i] + word
    if change > 1:
        for i in range(0,10):
            if number[change - 2] == str(i):
                word = decades[i] + word
    if change > 2:
        for i in range(0,10):
            if number[change - 3] == str(i):
                word = hundreds[i] + word
    change = change - 3
print(word)

Answer 1

这应该有效：word2number

以及他们的文档中的示例： print(w2n.word_to_num('one hundred thirty-five'))

Answer 2

几十年来，您错过了“七十”和“八十”之间的逗号。您必须将数十年更改为以下内容：

decades = ["", "twenty ", "thirty ", "forty ", "fifty ", "sixty ", "seventy", "eighty ", "ninety"]

在hunderds列表中也存在相同的错误。使用此新列表：

hundreds = ["", "one hundred ", "two hundred ", "three hundred ", "four hundred ", "five hundred", "six hundred ", "seven hundred", "eight hundred", "nine hundred"]

尽管如此，您的实现还是有很多错误。

Answer 3

这if语句将起作用（请注意，这是使它起作用所需的全部）：

if len(number)==1:
   print(ones[int(number)])
elif len(number)==2 and number[0]=='1':
   print(teens[int(number[-1])])
elif len(number)==2 and number[0]!='1':
   print(decades[int(number[0])-1])
elif len(number)==3:
   print(hundreds[int(number[0])])

请注意，必须在decades和hundreds中添加逗号，因此请复制以下内容，然后替换为剪贴板：

decades = ["", "twenty ", "thirty ", "forty ", "fifty ", "sixty ", "seventy", "eighty ", "ninety "]
hundreds = ["", "one hundred ", "two hundred ", "three hundred ", "four hundred ", "five hundred", "six hundred ", "seven hundred", "eight hundred",

Answer 4

我认为，为了使您的示例正常工作，您只需要确保每个change位数字都可以访问列表中的正确值即可。对于您的decades列表，情况并非如此，因为您错过了青少年的空白字符串，因此您正确地将其视为单独的情况。

因此，只需更改代码即可：

decades = ["", "twenty ", "thirty ", "forty ", "fifty ", "sixty ", "seventy", "eighty ", "ninety "]

对此：

decades = ["", "", "twenty ", "thirty ", "forty ", "fifty ", "sixty ", "seventy", "eighty ", "ninety "]

Answer 5

对于此实现，列表中应始终包含10个元素。例如，几十年来，即使不使用它，也应该有一些字符串表示10-20之间的值，因为否则数组的索引将是错误的。

仍然，此代码有很多错误。试试这个。

number = input("Enter a value: ")
ones = ["", "one ", "two ","three ", "four", "five ", "six ", "seven ", "eight ", "nine "]
teens = ["ten ", "eleven ", "twelve ", "thirteen ", "fourteen ", "fifteen ", "sixteen ", "seventeen ", "eighteen ", "nineteen "]
decades = ["", "onety", "twenty ", "thirty ", "forty ", "fifty ", "sixty ", "seventy ", "eighty ", "ninety "]
hundreds = ["", "one hundred ", "two hundred ", "three hundred ", "four hundred ", "five hundred", "six hundred ", "seven hundred", "eight hundred", "nine hundred"]

word = ""
change = len(number)

while change > 0:
    if number == "0":
        word ="zero"
        break
    elif change > 1 and number[change - 2] == "1":
        for i in range(0,10):
            if number[change - 1] == str(i):
                word = teens[i] + word
        if change == 2:
            break
    else:
        for i in range(0,10):
            if number[change - 1] == str(i):
                word = ones[i] + word
    if change > 1 and number[change-2]!="1":
        for i in range(0,10):
            if number[change - 2] == str(i):
                word = decades[i] + word
    if change > 2:
        for i in range(0,10):
            if number[change - 3] == str(i):
                word = hundreds[i] + word
    change = change - 3
print(word)

如何将数字转换为单词python 3

5 个答案: