我将事件记录存储在单个表中，开始和结束日期时间记录为单独的记录。
存储记录的表。
CREATE TABLE `avl_data` (
`id` bigint(20) unsigned NOT NULL AUTO_INCREMENT,
`imei_number` bigint(20) unsigned NOT NULL DEFAULT '0',
`latitude` double NOT NULL DEFAULT '0',
`longitude` double NOT NULL DEFAULT '0',
`report_id` tinyint(4) NOT NULL DEFAULT '0',
`rtc_date` datetime NOT NULL,
`ibutton_id` varchar(25) DEFAULT 'N/A',
`odometer` bigint(20) NOT NULL DEFAULT '0',
`speed` smallint(6) NOT NULL DEFAULT '0',
`vin_number` varchar(255) DEFAULT 'N/A',
`date_created` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
`time_report` int(11) NOT NULL DEFAULT '0',
PRIMARY KEY (`id`),
KEY `imei_number` (`imei_number`),
KEY `imei_rtc` (`imei_number`,`rtc_date`),
CONSTRAINT `avl_data_ibfk_1` FOREIGN KEY (`imei_number`) REFERENCES `assets` (`imei_number`) ON DELETE CASCADE
) ENGINE=InnoDB AUTO_INCREMENT=64916466 DEFAULT CHARSET=utf8 |`
这是我到目前为止尝试过的。
select concat(ass.label_1, " ", ass.label_2, " ", ass.label_3) as "Vehicle",
@start := case
when a.report_id = 103 then convert_tz(a.rtc_date, 'UTC', 'Asia/Kuwait') end as "Start",
@end := case
when a.report_id = 104 then convert_tz(a.rtc_date, 'UTC', 'Asia/Kuwait') end as "End",
TIMEDIFF(@start, @end) as 'Duration',
a.speed as 'Speed',
a.latitude as 'Latitude',
a.longitude as 'Longitude'
from avl_data a
inner join assets ass on a.imei_number = ass.imei_number
where a.imei_number = 356158069811103
and rtc_date >= '2018-10-01 00:00:00'
and rtc_date <= '2018-10-31 23:59:59'
and a.report_id in (103, 104)
order by a.rtc_date asc;
分别生成开始和事件记录，第一个记录是事件开始，第二个记录是事件停止。
+-------------------------------+---------------------+---------------------+----------+-------+-----------+-----------+
| Vehicle | Start | End | Duration | Speed | Latitude | Longitude |
+-------------------------------+---------------------+---------------------+----------+-------+-----------+-----------+
| Mitsubishi Outlander 14/74080 | 2018-10-01 08:29:26 | NULL | NULL | 128 | 29.045856 | 48.113764 |
| Mitsubishi Outlander 14/74080 | NULL | 2018-10-01 08:30:17 | NULL | 114 | 29.031169 | 48.121516 |
|
理想情况下，我想要一行，即
+-------------------------------+---------------------+---------------------+----------+-------+-----------+-----------+
| Vehicle | Start | End | Duration | Speed | Latitude | Longitude |
+-------------------------------+---------------------+---------------------+----------+-------+-----------+-----------+
| Mitsubishi Outlander 14/74080 | 2018-10-01 08:29:26 | 2018-10-01 08:30:17 | 00:01:17 | 128 | 29.045856 | 48.113764 |
感谢@Thorsten，这对我来说很有效。
select a.report_id as "ID",
any_value(case when a.report_id = 103 then concat(ass.label_1, ' ', ass.label_2, ' ', ass.label_3) end) as "Vehicle",
any_value(case when a.report_id = 103 then convert_tz(a.rtc_date, 'UTC', 'Asia/Kuwait') end) as "Start",
any_value(case when a.report_id = 103 then lead(convert_tz(a.rtc_date, 'UTC', 'Asia/Kuwait')) over () end) as "End",
any_value(case when a.report_id = 103 then SEC_TO_TIME(TIMESTAMPDIFF(SECOND , convert_tz(a.rtc_date, 'UTC', 'Asia/Kuwait'), lead(convert_tz(a.rtc_date, 'UTC', 'Asia/Kuwait')) over ())) end) as "Duration",
any_value(case when a.report_id = 103 then a.speed end) as "Speed",
any_value(case when a.report_id = 103 then a.latitude end) as "Latitude",
any_value(case when a.report_id = 103 then a.longitude end) as "Longitude"
from avl_data a
join assets ass on a.imei_number = ass.imei_number
where a.imei_number = 356158069811103
and a.rtc_date >= '2018-10-01 00:00:00'
and a.rtc_date <= '2018-10-31 23:59:59'
and a.report_id in (103, 104);
结果，尽管有办法删除现在为空的行？
+-----+-------------------------------+---------------------+---------------------+----------+-------+-----------+-----------+
| ID | Vehicle | Start | End | Duration | Speed | Latitude | Longitude |
+-----+-------------------------------+---------------------+---------------------+----------+-------+-----------+-----------+
| 103 | Mitsubishi Outlander 14/74080 | 2018-10-01 08:29:26 | 2018-10-01 08:30:17 | 00:00:51 | 128 | 29.045856 | 48.113764 |
| 104 | NULL | NULL | NULL | NULL | NULL | NULL | NULL |
| 103 | Mitsubishi Outlander 14/74080 | 2018-10-01 08:43:45 | 2018-10-01 08:44:14 | 00:00:29 | 136 | 29.067756 | 48.110384 |
| 104 | NULL | NULL | NULL | NULL | NULL | NULL | NULL |
| 103 | Mitsubishi Outlander 14/74080 | 2018-10-01 09:31:36 | 2018-10-01 09:31:44 | 00:00:08 | 135 | 29.056563 | 48.108851 |
| 104 | NULL | NULL | NULL | NULL | NULL | NULL | NULL |
| 103 | Mitsubishi Outlander 14/74080 | 2018-10-01 09:32:02 | 2018-10-01 09:33:54 | 00:01:52 | 149 | 29.048803 | 48.112581 |
| 104 | NULL | NULL | NULL | NULL | NULL | NULL | NULL |
| 103 | Mitsubishi Outlander 14/74080 | 2018-10-01 09:41:57 | 2018-10-01 09:42:35 | 00:00:38 | 131 | 29.036886 | 48.108733 |
| 104 | NULL | NULL | NULL | NULL | NULL | NULL | NULL |
| 103 | Mitsubishi Outlander 14/74080 | 2018-10-01 19:48:09 | 2018-10-01 19:48:20 | 00:00:11 | 126 | 29.034386 | 48.119706 |
| 104 | NULL | NULL | NULL | NULL | NULL | NULL | NULL |
答案 0 :(得分：0)
两行之间是否有公用密钥？
如果是这样，只需将avl_data表的2个实例连接在一起
类似
select convert_tz(aStart.rtc_date, 'UTC', tzone) as "Start",
convert_tz(aEnd.rtc_date, 'UTC', tzone) as "End",
from avl_data aStart
inner join avl_data aEnd on aStart.Key = aEnd.Key;
其中Key是公用密钥。
如果您没有公共密钥，而又依赖于另一行，那么您有一个主键序列，那么类似的事情可能会起作用
select convert_tz(aStart.rtc_date, 'UTC', tzone) as "Start",
convert_tz(aEnd.rtc_date, 'UTC', tzone) as "End",
from avl_data aStart
inner join avl_data aEnd on aStart.reportId + 1 = aEnd.reportId;
但是我不建议您这样做，因为它可能会使整个表的ID值比上一个值大1个。
像这样的东西可能会给你答案，但是它会产生额外的结果，因为它也会以End结尾。
select aStart.imei_number as "Imei",
convert_tz(aStart.rtc_date, 'UTC', tzone) as "Start",
convert_tz(MIN(aEnd.rtc_date), 'UTC', tzone) as "End"
from avl_data aStart
inner join avl_data aEnd on aStart.imei_number = aEnd.imei_number
and aStart.rtc_date < aEnd.rtc_date
group by aStart.imei_number, aStart.rtc_date, aStart.report_id
order by aStart.imei_number, aStart.rtc_date;
您可以将其用作子查询，并用排名值ref https://stackoverflow.com/a/1895127/3805124将其包装起来，然后删除偶数，因为它们应该是从结束记录开始的多余数。
答案 1 :(得分：0)
您可以使用聚合从两行中取出一行。当您需要来自report_id = 103的某些值和来自report_id = 104的某些值时，可以使用CASE WHEN获取一个值或另一个值。而且由于只有103行和104行，因此您的汇总函数是使用ANY_VALUE的伪汇总。
select
any_value(case when a.report_id = 103 then concat(ass.label_1, ' ', ass.label_2, ' ', ass.label_3) end) as "Vehicle",
any_value(case when a.report_id = 103 then convert_tz(a.rtc_date, 'UTC', 'Asia/Kuwait') end) as "Start",
any_value(case when a.report_id = 104 then convert_tz(a.rtc_date, 'UTC', 'Asia/Kuwait') end) as "End",
TIMEDIFF(
any_value(case when a.report_id = 103 then convert_tz(a.rtc_date, 'UTC', 'Asia/Kuwait') end),
any_value(case when a.report_id = 104 then convert_tz(a.rtc_date, 'UTC', 'Asia/Kuwait') end)
) as "Duration",
any_value(case when a.report_id = 103 then a.speed end) as "Speed",
any_value(case when a.report_id = 103 then a.latitude end) as "Latitude",
any_value(case when a.report_id = 103 then a.longitude end) as "Longitude"
from avl_data a
join assets ass on a.imei_number = ass.imei_number
where a.imei_number = 356158069811103
and rtc_date >= date '2018-10-01'
and rtc_date < date '2018-11-01'
and a.report_id in (103, 104);
替代方法是加入：
select
a103."Vehicle",
a103."Start",
a104."End",
TIMEDIFF(a103."Start", a104."End") as "Duration",
a103."Latitude",
a103."Longitude",
from
(
select
concat(ass.label_1, ' ', ass.label_2, ' ', ass.label_3) as "Vehicle",
convert_tz(a.rtc_date, 'UTC', 'Asia/Kuwait') end as "Start",
speed as "Speed",
latitude as "Latitude",
longitude as "Longitude"
from avl_data a
join assets ass on a.imei_number = ass.imei_number
where a.imei_number = 356158069811103
and rtc_date >= '2018-10-01 00:00:00'
and rtc_date <= '2018-10-31 23:59:59'
and a.report_id = 103
) a103
cross join
(
select convert_tz(a.rtc_date, 'UTC', 'Asia/Kuwait' as "End"
from avl_data a
join assets ass on a.imei_number = ass.imei_number
where a.imei_number = 356158069811103
and rtc_date >= '2018-10-01 00:00:00'
and rtc_date <= '2018-10-31 23:59:59'
and a.report_id = 104
) a104;