Mysql如果另一列满足条件，则删除所有匹配的值

Question

我有下表order_details：

|---------------------|------------------|------------------|
|      order_id       |    sap_number    |   product_name   |
|---------------------|------------------|------------------|
|          1          |         123      |     earphones    |
|---------------------|------------------|------------------|
|          2          |         123      |      battery     |
|---------------------|------------------|------------------|
|          3          |         456      |      charger     |
|---------------------|------------------|------------------|
|          4          |         789      |       phone      |
|---------------------|------------------|------------------|

如果产品是电池，我想删除所有具有相同sap_number的记录。在这种情况下，我希望删除具有order_id 1和2的记录。

我尝试过：

delete from order_details 
where order_id in (
  select order_id
  from (
      select order_id
      from order_details
      group by sap_number
      having product = 'battery'
      ) t
)

但它仅删除第二条记录，而不删除第一条记录。

谢谢。

Answer 1

您可以在下面尝试

delete from order_details 
where sap_number in (
      select sap_number
      from order_details
      where product_name= 'battery'
      ) 

Answer 2

尝试

 delete from order_details where sap_number IN (select sap_number from (select * from order_details  having product_name = 'battery') t);