Question

原谅尴尬的问题标题，我不确定该如何表达...

我有一个观察对象，它返回一个Form对象。

export class QuestionConfiguration {
    //...
}

export class Question {
    configure(qc: QuestionConfiguration) {
        // set variables...
    };
}

export class Form {
    constructor(public question: Question[]) {}
}

// lets assume this does a http call and returns an instanstiated list of forms.
let doFormsRequest$ = (): Observable<Forms[]> =>  {
}

还有另一种方法，它返回question的每个内部Form.questions的配置：

let getQuestionConfiguration$ = (question: Question): Observable<QuestionConfiguration> {
    // ...
}

我希望创建一个ReplaySubject(1)来作为可观察对象的观察者，该观察对象将每个问题配置为questionConfiguration可观察对象，并且仅在所有子问题均已配置后才返回。

有什么方法可以通过管道/地图/第一个可观察到的方式返回完全配置的表单来实现这一目标？

类似：

// using this as an observer so the configuration logic only happens once.
let mySubject: Subject<Form[]> = new ReplaySubject(1);

doFormsRequest$().pipe(
    someOperator((forms: Forms[]) => {
        // returns the configured form after calling and modifying each question according to the output of the getQuestionConfiguration observable
        // i.e. question.configure(qc: QuestionConfiguration);
    })
).subscribe(mySubject);

配置可观察输出内的对象列表

0 个答案: