Question

我有一个名为olmali的数组

$olmali = $_POST['result'];

和

print_r($olmali);

结果如下：

Array ( 
    [0] => 1
    [1] => 1
    [2] => 20
    [3] => 2 
    [4] => 3
    [5] => 5
    [6] => 6 
    [7] => 7 
    [8] => 9 
    [9] => 8 
    [10] => 10
    [11] => 11
    [12] => 13
    [13] => 12 
    [14] => 12
    [15] => 14 
    [16] => 15
    [17] => 16
    [18] => 17
    [19] => 17
    [20] => 19
    [21] => 20
)

我想使用SQL UPDATE命令，我期望：

id        test
1          1
2          1
3          20
4          2
5          3
6         ....and goes on

如何解决此问题？有什么办法，我该怎么办。 PHP数组使用这样的UPDATE SQL命令到MySQL表中的列行

Answer 1

假设

public static void main(String[] args) {

    String string = "Hello";
    // you can call `mapBoo` like normal here
    string = mapBoo(string);
    System.out.println(string);

    List<String> strings = Arrays.asList("Hello", "this", "is", "a", "test");

    // or you can pass mapBoo into the stream.map method since map fits the method signature
    List<String> mappedStrings = strings.stream().map(Main::mapBoo)
            .collect(Collectors.toList());

    for (String mappedString : mappedStrings)
        System.out.println(mappedString);
}


static String mapBoo(String s) {
    return s + "boo";
}

然后使用PDO建立数据库连接后，准备绑定并执行

    $myArray = array ( 
        [0] => 1
        [1] => 1
        [2] => 20
        [3] => 2 
        [4] => 3
        [5] => 5
        [6] => 6 
        [7] => 7 
        [8] => 9 
        [9] => 8 
        [10] => 10
        [11] => 11
        [12] => 13
        [13] => 12 
        [14] => 12
        [15] => 14 
        [16] => 15
        [17] => 16
        [18] => 17
        [19] => 17
        [20] => 19
        [21] => 20
    );

Answer 2

我建议从C2 = TRIM(RIGHT(A2,LEN(A2)-SEARCH(CHAR(32),TRIM(A2),SEARCH(CHAR(32),TRIM(A2))+1)))循环开始，并为每个键重新分配值for。然后，您只需要使用+1删除数组的第一个索引。请参见下面的代码。

unset()

输出：

$olmali = [
  0 => 1,
  1 => 1,
  2 => 20,
  3 => 2,
  4 => 3,
  5 => 5,
  6 => 6,
  7 => 7,
  8 => 9,
  9 => 8,
  10 => 10,
  11 => 11,
  12 => 13,
  13 => 12,
  14 => 12,
  15 => 14,
  16 => 15,
  17 => 16,
  18 => 17,
  19 => 17,
  20 => 19,
  21 => 20
];

for($i = count($olmali); $i > 0; $i--) {
  $olmali[$i] = $olmali[$i - 1];
}

unset($olmali[0]);

print_r($olmali);

到MySQL表中带有SQL Update列的数组到列行

2 个答案: