我想创建并填充以下否。 SQL(SQL服务器)在Curr.Status中输入的条目数(如下所示)。
ID Sequence Prev.Status Curr.Status No. of Entries in Curr.Status
9-9999-9 1 Status D Status A 1
9-9999-9 2 Status A Status A 2
9-9999-9 3 Status A Status A 3
9-9999-9 4 Status A Status A 4
9-9999-9 5 Status A Status B 1
9-9999-9 6 Status B Status B 2
9-9999-9 7 Status B Status B 3
9-9999-9 8 Status B Status A 1
9-9999-9 9 Status A Status A 2
9-9999-9 10 Status A Status C 1
9-9999-9 11 Status C Status C 2
是否有使用row_number()
之类的快捷方法(仅此一项似乎还不够)来创建我要寻找的字段?
谢谢!
答案 0 :(得分:1)
这似乎是一个“团体和岛屿”问题。但是,有很多关于如何实现此目标的示例:
WITH VTE AS(
SELECT *
FROM (VALUES('9-9999-9',1 ,'Status D','Status A'),
('9-9999-9',2 ,'Status A','Status A'),
('9-9999-9',3 ,'Status A','Status A'),
('9-9999-9',4 ,'Status A','Status A'),
('9-9999-9',5 ,'Status A','Status B'),
('9-9999-9',6 ,'Status B','Status B'),
('9-9999-9',7 ,'Status B','Status B'),
('9-9999-9',8 ,'Status B','Status A'),
('9-9999-9',9 ,'Status A','Status A'),
('9-9999-9',10,'Status A','Status C'),
('9-9999-9',11,'Status C','Status C')) V(ID, Sequence, PrevStatus,CurrStatus)),
CTE AS(
SELECT ID,
[Sequence],
PrevStatus,
CurrStatus,
ROW_NUMBER() OVER (PARTITION BY ID ORDER BY [Sequence]) -
ROW_NUMBER() OVER (PARTITION BY ID,CurrStatus ORDER BY [Sequence]) AS Grp
FROM VTE V)
SELECT ID,
[Sequence],
PrevStatus,
CurrStatus,
ROW_NUMBER() OVER (PARTITION BY Grp ORDER BY [Sequence]) AS Entries
FROM CTE;
答案 1 :(得分:0)
如果Sequence
是标识列,则可以执行以下操作:
select t.*,
row_number() over (partition by (Sequence - seq) order by Sequence) as [No. of Entries in Curr.Status]
from (select t.*,
row_number() over (partition by [Curr.Status] order by Sequence) as seq
from table t
) t;
否则,您需要生成两个row_numbers
:
select t.*,
row_number() over (partition by (seq1- seq2) order by Sequence) as [No. of Entries in Curr.Status]
from (select t.*,
row_number() over (partition by id order by Sequence) as seq1
row_number() over (partition by id, [Curr.Status] order by Sequence) as seq2
from table t
) t;
答案 2 :(得分:0)
您可以使用LAG
功能标记状态更改的行,并使用SUM() OVER ()
为每个组分配唯一编号。组内的编号很简单:
DECLARE @t TABLE (ID VARCHAR(100), Sequence INT, PrevStatus VARCHAR(100), CurrStatus VARCHAR(100));
INSERT INTO @t VALUES
('9-9999-9', 1, 'Status D', 'Status A'),
('9-9999-9', 2, 'Status A', 'Status A'),
('9-9999-9', 3, 'Status A', 'Status A'),
('9-9999-9', 4, 'Status A', 'Status A'),
('9-9999-9', 5, 'Status A', 'Status B'),
('9-9999-9', 6, 'Status B', 'Status B'),
('9-9999-9', 7, 'Status B', 'Status B'),
('9-9999-9', 8, 'Status B', 'Status A'),
('9-9999-9', 9, 'Status A', 'Status A'),
('9-9999-9', 10, 'Status A', 'Status C'),
('9-9999-9', 11, 'Status C', 'Status C');
WITH cte1 AS (
SELECT *, CASE WHEN LAG(CurrStatus) OVER(ORDER BY Sequence) = CurrStatus THEN 0 ELSE 1 END AS chg
FROM @t
), cte2 AS (
SELECT *, SUM(chg) OVER(ORDER BY Sequence) AS grp
FROM cte1
), cte3 AS (
SELECT *, ROW_NUMBER() OVER(PARTITION BY grp ORDER BY Sequence) AS SeqInGroup
FROM cte2
)
SELECT *
FROM cte3
ORDER BY Sequence