Question

我开始构建一个android应用程序（顺便说一句，我是android的新手，对Java并不熟悉）。我希望它对服务器执行GET-Request，获取一个json，然后对该json执行某些操作。

下面的代码可以正常工作，但是它很长，我可以想象在实现此活动中的几个按钮后，这真是一团糟

public class secondActivity extends Activity implements OnClickListener {
@Override
public void onCreate(final Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    this.setContentView(R.layout.login_formular);
    View v = findViewById(R.id.button2);
    v.setOnClickListener(this);

}

@Override
public void onClick(View v) {
    if(v.getId() == R.id.button2) {
        OkHttpClient client = new OkHttpClient();
        String url="https://example.com/json";
        Request request= new Request.Builder()
                .url(url)
                .build();
        client.newCall(request).enqueue(new Callback() {
            @Override
            public void onFailure(Call call, IOException e) {
                e.printStackTrace();
            }

            @Override
            public void onResponse(Call call, Response response) throws IOException {
                if(response.isSuccessful()){
                    final String res= response.body().string();
                    final Gson gson= new Gson();
                    final Employee employee=gson.fromJson(res, Employee.class);
                    secondActivity.this.runOnUiThread(new Runnable() {
                        @Override
                        public void run() {
                            TextView txt= findViewById(R.id.txt3);
                            txt.setText("employee: " + employee.name);
                        }
                    });
                }
            }
        });
    }
}
}

我的想法是将http和onclick事件内部的代码外包给新类，但此函数不起作用。

该请求运行正常，但我的员工仅存在于onResponse中，我不知道如何退回该请求。

getEmployeeName.java

public class getEmployeeName {
public static String reqName(){
    OkHttpClient client = new OkHttpClient();
    String url="https://example.com/json";
    Request request= new Request.Builder()
            .url(url)
            .build();
    client.newCall(request).enqueue(new Callback() {
        @Override
        public void onFailure(Call call, IOException e) {
            e.printStackTrace();
        }
        @Override
        public void onResponse(Call call, Response response) throws IOException {

            if(response.isSuccessful()){
                String res= response.body().string();
                Gson gson= new Gson();
                Employee employee=gson.fromJson(res, Employee.class);
            }
        }
    });
    return employee;
}
}

secondActivity.java

public void onClick(View v) {
    if(v.getId() == R.id.button2) {
        String name = getEmployeeName.reqName();
        secondActivity.this.runOnUiThread(new Runnable() {
            @Override
            public void run() {
                TextView txt= findViewById(R.id.txt3);
                txt.setText("employee: " + name);
            }
        });
    }
}

我做错了什么？谢谢阿米特（Amit）

将HTTP请求外包给新类

0 个答案: