奇怪的铸造行为

Question

我有一个int *arr[3];数组，其元素像这样初始化：

sides[0] = &a;
sides[1] = &b;
sides[2] = &c;

其中a = b = 5和c = 10。现在，当我尝试强制转换每个指针指向的内存地址的内容的值的类型（从int到double）时，第3个值始终显示为0。您知道为什么吗？

这就是我在做什么：

double a,b,c;
a = (double) *sides[0];
b = (double) *sides[1];
c = (double) *sides[2];
printf("%lf %lf %lf",a,b,c);

我得到的output是：

5.0000 5.0000 0.0000

这是完整的代码：

    #include <stdio.h>
#include <math.h>

void populateSides(int *[3]);
void calculateTriangleType(int *[3]);

/*
* Function populateSides: Has 1 arg
* 1st arg: an array of int *.
* This function stores the 3 sides of a triangle 
* given by the user into the sides array.
*/
void populateSides(int *sides[]) {
    int i,a,b,c;
    scanf(" %d",&a);
    scanf(" %d",&b);
    scanf(" %d",&c);
    while((c <= b) || (c <= a)) {
        scanf(" %d",&c);
    }
    sides[0] = &a;
    sides[1] = &b;
    sides[2] = &c;
}

/*
*/
void calculateTriangleType(int *sides[]) {
    double a,b,c;
    a = (double) *sides[0];
    b = (double) *sides[1];
    c = (double) *sides[2];
    printf("%lf %lf %lf",a,b,c);

}

int main(void) { // Stelios Papamichail 4020
    int *sides[3]; // stores each side of a triangle ( >0)
    populateSides(sides);
    calculateTriangleType(sides);
    return 0;
}