Question

尝试将csv读入列表。

代码如下：

import csv

with open('file.csv','r') as fin:
    reader = csv.reader(fin)
    mylist = list(reader)

print (mylist)

def gen_list():
    with open('file.csv','r') as fin:
        reader = csv.reader(fin)
        mylist = list(reader)
    print (mylist)

def main():
    gen_list()
    return 0

我的输出是：

[['one','two','three']]

Traceback():
....
line 11, in gen_list
reader = csv.reader(fin)
AttributeError: 'str' object has no attribute 'reader'

我可以通过将“ import csv”作为gen_list函数的第一行来防止发生此错误。

为什么将代码放在函数中不起作用？

Answer 1

结果是我偶然在另一个函数中使用了csv。一旦我更改了csv，问题就消失了

功能：

def get_list(csv):
    with open(csv,'rt') as fin:
        for line in fin:
            drList.append(gen_list(line))
        return (drList)

Answer 2

尝试一下：

import csv

with open('file.csv','r') as fin:
    reader = csv.reader(fin)
    mylist = list(reader)

print (mylist)

def gen_list():
    with open('file.csv','r') as fin:
        reader = csv.reader(fin)
        mylist = list(reader)
    print (mylist)

def main():
    gen_list()
    return 0

reader中open中gen_list的缩进似乎是错误的

Python函数看不到导入的模块

2 个答案: