Question

我正在尝试在c ++中打印一个二维数组，但是我遇到了问题。我遵循传统的方法在for循环中打印向量const mongoose = require('mongoose'); const variantSchema = new mongoose.Schema({ title: String, available: Number, _sku: String, _skuSuffix: String, }); variantSchema.virtual('skuSuffix') .set(function setSkuSuffix(skuSuffix) { if (!skuSuffix) return; const parent = this.parent(); if (parent._skuPrefix) { child._sku = `${parent._skuPrefix}-${child._skuSuffix}`; } }) .get(function getSkuSuffix() { return this._skuSuffix; }); variantSchema.virtual('sku').get(function getSku() { return this._sku; }); module.exports = variantSchema;。所以我遵循的方式是这样。

const product = new Product(jsonObj);

但这就是这样打印

      let variant;
      if (jsonObj.variants) {
        variant = jsonObj.variants;
        delete jsonObj.variants;
      }
      const newProduct = new Product(jsonObj);
      if (variant) {
        if (newProduct.variants.length) {
          // copy function detail not shown
          copyFromObjToProduct(variant, newProduct.variants[0]);
        } else {
          newProduct.variants.push(variant);
        }
      }

预期输出

vectorName.size()

如何正确打印矢量？

Answer 1

问题基本上是如何填充向量：

User.html

更高效，因为您仍然希望拥有相同的数据：

Dim sr As Series
For Each sr In ct.SeriesCollection
    sr.Delete
Next

With ct.SeriesCollection.NewSeries
    .Name = "A"
    .Values = a
    .XValues = x
End With

With ct.SeriesCollection.NewSeries
    .Name = "B"
    .Values = b
    .XValues = x
End With

With ct.SeriesCollection.NewSeries
    .Name = "C"
    .Values = c
    .XValues = x
End With

Answer 2

打印std::vector中的std::vector的两种简单方法：

#include <vector>
#include <iostream>

int main()
{
    std::vector<std::vector<int>> foo{
        { 0, 1, 2, 3, 4 },
        { 0, 1, 2, 3, 4 },
        { 0, 1, 2, 3, 4 },
        { 0, 1, 2, 3, 4 }
    };

    // range-based for-loops:
    for (auto const &row : foo) {
        for (auto const &col : row) {
            std::cout << col << ' ';
        }
        std::cout.put('\n');
    }

    std::cout.put('\n');

    // ordinary for-loops:
    for (std::size_t row{}; row < foo.size(); ++row) {
        for (std::size_t col{}; col < foo[row].size(); ++col) {
            std::cout << foo[row][col] << ' ';
        }
        std::cout.put('\n');
    }
}

打印矢量

2 个答案: