我的日期格式为Apr42016，Aug12017，Apr112018。我正在尝试使用R在Y / m / d中进行转换。我尝试了以下代码，但是当返回日期为NA时只有一位数字。有人可以帮助我吗？
strptime(data$date, "%b%e%Y")
as.Date (data$date, format="%b%d%Y")
as.POSIXct(data$date, format="%b%e%Y")
谢谢
答案 0 :(得分：2)
如果您可以分解CREATE TABLE `bwc_master`(
unique_id bigint,
customer_id string,
direction string,
call_date_time timestamp,
duration int,
billed_duration int,
retail_rate decimal(9,7),
retail_cost decimal(19,7),
billed_tier smallint,
call_type tinyint,
record_status tinyint,
aggregate_id bigint,
originating_ipaddress string,
originating_number string,
destination_number string,
lrn string,
ocn string,
destination_rate_center string,
destination_lata int,
billed_prefix string,
rate_id string,
wholesale_rate decimal(9,7),
wholesale_cost decimal(19,7),
cnam_dipped boolean,
billed_number_type tinyint,
source_lata int,
source_ocn string,
location_id string,
sippeer_id int,
rate_attempts tinyint,
source_state string,
source_rc string,
destination_country string,
destination_state string,
destination_ip string,
carrier_id string,
rated_date_time timestamp,
partition_id smallint,
encryption_rate decimal(9,7),
encryption_cost decimal(19,7),
trans_coding_rate decimal(9,7),
trans_coding_cost decimal(19,7),
file_name string,
call_id string,
from_tag string,
to_tag string,
unique_record_id string)
PARTITIONED BY (
`call_date` date)
CLUSTERED BY (
customer_id)
INTO 10 BUCKETS
ROW FORMAT SERDE
'org.apache.hadoop.hive.ql.io.orc.OrcSerde'
STORED AS INPUTFORMAT
'org.apache.hadoop.hive.ql.io.orc.OrcInputFormat'
OUTPUTFORMAT
'org.apache.hadoop.hive.ql.io.orc.OrcOutputFormat'
LOCATION
'hdfs://*****/apps/hive/warehouse/dtc.db/bwc_master'
之前的数字，则将使事情变得容易得多。 （借用Sven的回头率。）
as.Date从这里开始，格式应该相当简单：
sub("(?<=\\D)(\\d+)(\\d{4})$", "-\\1-\\2",
c("Apr42016", "Aug12017", "Apr112018"), perl=TRUE)
# [1] "Apr-4-2016" "Aug-1-2017" "Apr-11-2018"
答案 1 :(得分：2)
在使用df %>%
mutate_at(vars(life_expectancy, poverty, household_income),
function(x) map(x, round, digits = c(1, 2, 0))) %>%
unnest()
#> # A tibble: 3 x 4
#> name life_expectancy poverty household_income
#> <chr> <dbl> <dbl> <dbl>
#> 1 New Haven 78.1 0.3 42589.
#> 2 New Haven 78.1 0.26 42589.
#> 3 New Haven 78 0 42589
之前，您可以使用sub修改字符串（并在必要时添加0）。
as.Date