这是我的查询
CREATE VIEW marksheet as
SELECT name as name, student_id as student_id,
roll as roll, class as class,exam_year as exam_year,
subject_name as subject, exam_type as exam_type,
sum(full_mark) as full_mark, sum(getmark) as getmark,
department as department,
IF(SUM(IF(gpa='f' OR gpa='F',-9999,gpa))>=0,
CAST(IF(subject_type=1,SUM(gpa)-2/count(subject_name),SUM(gpa)/count(subject_name))
AS CHAR), 'F') as total_gpa
FROM mark
GROUP by roll, class, exam_type
不起作用
IF(subject_type=1,SUM(gpa)-2/count(subject_name),SUM(gpa)/count(subject_name))
每次只能工作else
情况SUM(gpa)/count(subject_name
不起作用subject_type=1,SUM(gpa)-2/count(subject_name)
我的桌子
结果:gpa = 5 + 8 + 4 + 6
= 23
但是subject_type = 1 so ,minus -2
(无效)
= 21 (Not work)
最终Gpa = 21 / count(subject_name)
答案 0 :(得分:0)
如果只有一门额外的科目(即具有subject_type=1
的科目,而所有其他科目都有subject_type=0
,则可以使用MAX(subject_type)
来确定学生是否参加了一门额外的科目。此查询应该执行您想要的操作(请注意,您还需要在()
周围加上SUM(gpa)-2
)
CREATE VIEW marksheet as
SELECT name as name, student_id as student_id,
roll as roll, class as class,exam_year as exam_year,
subject_name as subject, exam_type as exam_type,
sum(full_mark) as full_mark, sum(getmark) as getmark,
department as department,
IF(SUM(IF(gpa='f' OR gpa='F',-9999,gpa))>=0,
CAST(IF(MAX(subject_type)=1,(SUM(gpa)-2)/count(subject_name),SUM(gpa)/count(subject_name))
AS CHAR), 'F') as total_gpa
FROM mark
GROUP by roll, class, exam_type
我在SQLFiddle创建了一个简化的演示。