Question

我正在尝试从以下类似的数据库中计算时间平均时差和票数：

[TicketId | OpenedDateTime      | ResponseDateTime    | Category  ]
[12345    | 2018-11-11 15:03:02 | 2018-11-11 15:08:19 | Helpdesk  ]
[12346    | 2018-11-11 15:06:00 | 2018-11-11 15:18:26 | Helpdesk  ]
[12347    | 2018-11-11 15:09:58 | 2018-11-11 15:11:11 | Support   ]
[12348    | 2018-11-11 15:11:33 | 2018-11-11 15:28:56 | Headphones]
[12349    | 2018-11-11 15:12:12 | 2018-11-11 15:15:15 | Support   ]

目前，我逐行计算OpenedDateTime和ResponseDateTime之间的时间差。

SELECT 
    [OpenedDateTime],
    [ResponseDateTime],
    RIGHT('0' + LTRIM(convert(varchar(5),DateDiff(s, [OpenedDateTime], [ResponseDateTime])/3600)), 2) + ':' +
    RIGHT('0' + LTRIM(convert(varchar(5),DateDiff(s, [OpenedDateTime], [ResponseDateTime])%3600/60)), 2) + ':' +
    RIGHT('0' + LTRIM(convert(varchar(5),(DateDiff(s, [OpenedDateTime], [ResponseDateTime])%60))), 2) as 'TimeDifference'
FROM 
    [dbo].[ticket]

我最后需要做的是：

[Category   | TotalTickets | AverageResponseTime]
[Helpdesk   | 2            | 00:09:11           ]
[Support    | 2            | 00:02:33           ]
[Headphones | 1            | 00:17:23           ]

关于如何实现此目标的任何建议？

SQL平均时差hh：mm：ss按类型

0 个答案: