我想在dropdownlist
命中时在每一行中获得addrow button
。
我不知道该怎么做。
这是我拥有的:
$('#addrow').click(function () {
var tr = "<tr><td>@@Html.DropDownList(\"Bank\", null, htmlAttributes: new { @@class = \"form-control\" })"
+ "</td><td><div>"
+ "<div class=\"input-group date\">"
+ "<div class=\"input-group-addon\"><i class=\"fa fa-calendar\"></i>"
+ "</div>"
+ "<input type=\"text\" class=\"form-control ChqDate\" name=\"ChqDate\" placeholder=\"Chq Date\">"
+ "</div><!-- /.input group -->"
+ "</div></td>"
+ "<td><input type=\"number\" name=\"Amount\" class=\"form-control\" id=\"ChqAmount\" placeholder=\"Cheque Amount\" /></td>"
+ "<td><button data-itemId=\"0\" type=\"button\" class=\"btn btn-danger removeRow\"><span class=\"glyphicon glyphicon-trash\"></span></button></td></tr>";
$('#example1 tbody').append(tr);
$('#example1 tbody .ChqDate').datepicker({
autoclose: true
});
});
答案 0 :(得分:1)
首先在视图中显示下拉菜单(但用户看不见):
@Html.DropDownList("Bank-Template", null, htmlAttributes: new { style="display: none;", id="Bank-Template" })
,然后在javascript中将其用作模板:
$('#addrow').click(function () {
var tr = "<tr><td><select name=\"Bank\" class=\"form-control\">" + $("#Bank-Template").html()
+ "</select></td><td><div>"
+ "<div class=\"input-group date\">"
+ "<div class=\"input-group-addon\"><i class=\"fa fa-calendar\"></i>"
+ "</div>"
+ "<input type=\"text\" class=\"form-control ChqDate\" name=\"ChqDate\" placeholder=\"Chq Date\">"
+ "</div><!-- /.input group -->"
+ "</div></td>"
+ "<td><input type=\"number\" name=\"Amount\" class=\"form-control\" id=\"ChqAmount\" placeholder=\"Cheque Amount\" /></td>"
+ "<td><button data-itemId=\"0\" type=\"button\" class=\"btn btn-danger removeRow\"><span class=\"glyphicon glyphicon-trash\"></span></button></td></tr>";
$('#example1 tbody').append(tr);
$('#example1 tbody .ChqDate').datepicker({
autoclose: true
});
});
,但是必须为控件设置唯一的名称,否则数据可能以数组形式发布到服务器。例如ChqDate [0],Bank [0],ChqDate [1],Bank [1],...