Question

我对Python或SQL不太熟悉，并且受命创建一个搜索结果页面以显示SQL数据库中的用户信息。我正在使用flask，将JSON对象从python后端发送到javascript / jquery前端。当一个搜索（通过电子邮件地址进行搜索）返回的用户只有一个使用以下代码时，我设法显示了一个用户：

 user = db.execute(
            'SELECT * FROM user WHERE email = ?', (emailInput,)
        ).fetchone()
        if user is None:
            user_details = {
                'first' : 'error'
            }
            y = json.dumps(user_details)
            return jsonify(y)
        if user['first'] is None:
            first = ""
        else:
            first = user['first']
        if user['email'] is None:
            email = ""
        else:
            email = user['email']
        if user['last'] is None:
            last = ""
        else:
            last = user['last']
        if user['address_line1'] is None:
            address_line1 = ""
        else:
            address_line1 = user['address_line1']
        if user['address_line2'] is None:
            address_line2 = ""
        else:
            address_line2 = user['address_line2']
        if user['username'] is None:
            username = ""
        else:
            username = user['username']
        user_details = {
            'first': first,
            'last': last,
            'email': email,
            'address1': address_line1,
            'address2': address_line2,
            'username': username
        }
        y = json.dumps(user_details)
        return jsonify(y)

现在，我想使用fetchall（）升级此代码，以返回通过SQL调用获取的每个用户的user_details，但我不知道该怎么做。预先感谢您的帮助。

编辑：我真正需要帮助的是将多个结构变成这样：

    user_details = {
        'first': first,
        'last': last,
        'email': email,
        'address1': address_line1,
        'address2': address_line2,
        'username': username
    }

变成这样的一个大结构：

        users = {
            user_details1 = {
                'first': first,
                'last': last,
                'email': email,
                'address1': address_line1,
                'address2': address_line2,
                'username': username
            }
            user_details2 = {
                'first': first,
                'last': last,
                'email': email,
                'address1': address_line1,
                'address2': address_line2,
                'username': username
            }
            etc.
        }

Answer 1

不用花几个小时来解决这个特定的SQL问题，而是花几个小时来学习an ORM like sqlalchemy，这样您就不必再写SQL了：）

Answer 2

fetchall返回一个列表列表，因此您只需要遍历外部列表（表的行）。例如：

users = db.execute(
            'SELECT * FROM user WHERE email = ?', (emailInput,)
        ).fetchall()
for user in users:
        if user['first'] is None:
            <etc>

用Python编译用户的字典以获取搜索结果

2 个答案: