For循环连接SQL结果

Question

我正在尝试创建一个函数，该函数带有一个列表“ teams”，运行一个SQL查询，使用for循环检索每个团队的结果，将结果返回到数据帧中它们各自的字段，然后连接数据端并排。因此理想情况下，结果应如下所示：

我下面的代码产生错误：“'列表'对象没有属性'concat'”。有人可以建议我如何实现期望的输出吗？

谢谢！

teams = ['Chicago','Orlando','Miami','New York']

class Team:
    Date = datetime(1900,1,1)
    Pts_Scored = 0

def myfunct(conn, teams):
    curr = conn.cursor()
    pts_scored = []

    for t in teams:
        curr.execute("select date, pts_scored from db.teams where teams ='"+t+"'")
        for i in curr:
            point_hist = Team()
            point_hist.Date = i[1]
            point_hist.Pts_Scored = i[2]
            pts_scored.concat(point_hist)

Answer 1

pts_scored应该是字典，其键是日期。值应该是另一本字典，其关键字是团队名称，值是分数。

def myfunct(conn, teams):
    curr = conn.cursor()
    pts_scored = {}

    curr.execute("select date, pts_scored, teams from db.teams")
    for i in curr:
        if i['teams'] in teams:
            if i['date'] not in pts_scored:
                pts_scores[i['date']] = {}
            point_hist[i['date']][i['teams'] = i['pts_scored']

然后您可以使用嵌套循环来打印表：

# print heading
for team in teams:
    print("Date", team, end='')
print("")
# print results
for date, results in point_hist.items():
    for team in teams
        print(date, results[team], end='')
    print("")