在python中使用raw_input的两个数字的总和

Question

我要执行此操作：

从STDIN读取两个整数并在其中打印三行：

第一行包含两个数字的总和。 第二行包含两个数字的差（第一-第二）。 第三行包含两个数字的乘积。

有人可以帮我吗？

Answer 1

慢慢开始并分解

# Get your data from the user, use input
num_one = input("Please enter the first number: ")
num_two = input("Please enter the second number: ")

# Create the sum, diff, and product, casting as integer
sum = int(num_one) + int(num_two)
diff = int(num_one) - int(num_two)
product = int(num_one) * int(num_two)

# Print each output casting as a string since we can't concatenate a string to an integer
print("The sum is: "+str(sum))
print("The difference is: "+str(diff))
print("The product is: "+str(product))

现在，您还应该在此处进行一些错误检查，以防用户不输入任何内容：

 # Get your data from the user, use input
num_one = input("Please enter the first number: ")
num_two = input("Please enter the second number: ")

if(num_one == "" or num_two == ""):
    print("You did not enter enter two numbers. Exiting...")
    exit
else:
    # Create the sum, diff, and product, casting as integer
    sum = int(num_one) + int(num_two)
    diff = int(num_one) - int(num_two)
    product = int(num_one) * int(num_two)

    # Print each output casting as a string since we can't concatenate a 
    string to an integer
    print("The sum is: "+str(sum))
    print("The difference is: "+str(diff))
    print("The product is: "+str(product))

Answer 2

Python 2.7

raw_input读取输入，int将字符串转换为整数，print打印输出

a = int(raw_input("numebr 1: "))
b = int(raw_input("numebr 2: "))
print a + b
print a - b
print a * b

Python 3.7

input读取输入，int将字符串转换为整数，将输出打印到print，

a = int(input("numebr 1: "))
b = int(input("numebr 2: "))
print (a + b)
print (a - b)
print (a * b)

Answer 3

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