使用git show
,我可以从特定提交中获取特定文件的内容,而无需更改本地克隆的状态:
$ git show <file>
$ git show <commit>:<file>
如何使用libgit2sharp以编程方式实现这一目标?
答案 0 :(得分:4)
$ git show 807736c691865a8f03c6f433d90db16d2ac7a005:a.txt
等效于以下代码:
using System;
using System.IO;
using System.Linq;
using System.Text;
using LibGit2Sharp;
namespace ConsoleApp2
{
class Program
{
static void Main(string[] args)
{
var pathToFile = "a.txt";
var commitSha = "807736c691865a8f03c6f433d90db16d2ac7a005";
var repoPath = @"path/to/repo";
using (var repo =
new Repository(repoPath))
{
var commit = repo.Commits.Single(c => c.Sha == commitSha);
var file = commit[pathToFile];
var blob = file.Target as Blob;
using (var content = new StreamReader(blob.GetContentStream(), Encoding.UTF8))
{
var fileContent = content.ReadToEnd();
Console.WriteLine(fileContent);
}
}
}
}
}
答案 1 :(得分:0)
作为null令牌says in the comments,Lookup<T>()
can use冒号路径规范语法。
using (var repo = new Repository(repoPath))
{
// This line is the change from Andrzej Gis
var blob = repo.Lookup<Blob>(commitSha + ":" + path);
using (var content = new StreamReader(blob.GetContentStream(), Encoding.UTF8))
{
var fileContent = content.ReadToEnd();
Console.WriteLine(fileContent);
}
}