Question

我有带有对象列表作为值的字典。

class Device_Terminals():
    """Class for define object for each device"""
    def __init__(self, device_name, source, drain):
        self.device_name = device_name
        self.source = source
        self.drain = drain

device = Device_Terminals(line[0], line[1], line[3])
if line[2] not in devices_dict:
        devices_dict[line[2]] = []
devices_dict[line[2]].append(device)

我想返回其对象之一具有特定名称的键，字典如下所示

{A1:[ MNA1 X_N1 VSS, MPA1_1 X X_P1_1, MPA1_2 X X_P1_2, MPA1_3 X X_P1_3, MPA1_4 X X_P1_4, MPA1_5 X X_P1_5, MPA1_6 X X_P1_6, MPA1_7 X X_P1_7], 'A3': [MNA3 X_N1 VSS, MPA3_1 X_P2_1 VDD, MPA3_2 X_P2_2 VDD, MPA3_3 X_P2_3 VDD, MPA3_4 X_P2_4 VDD, MPA3_5 X_P2_5 VDD]}

列表中的每个元素都是一个对象。如何返回其

值的键

 device_name == MPA3_3: 
   return key

Answer 1

您可以从defaultdict创建collections而不是先检查密钥是否存在然后附加到密钥。

from collections import defaultdict
devices_dict = defaultdict(list)

要添加到此字典中：

device = Device_Terminals(line[0], line[1], line[3])
devices_dict[line[2]].append(device)

要搜索其值，请在字典上放置一个简单的循环：

# your search term
search_val = 'device_name'
for key, devices in devices_dict.items():
    for device in devices:
        if search_val == device.device_name:
            print(key)

Answer 2

如果您尝试使用其值进行字典查找。尝试看看这个先前回答的问题的解决方案。

Get key by value in dictionary

获取具有其值的特定属性的密钥

2 个答案: