在PostgreSQL中分开时间

Question

如何在PostgreSQL中运行以下查询（以下内容适用于MSSQL）。目的是看看发生了多少时间分开：

select ABS(CAST((a.timefield - b.timefield) as INT)) as 'Time Apart'
from a inner join b on (a.id = b.id);

Answer 1

根据“a.timefield”和“b.timefield”的类型，这应该有效：

SELECT ABS(EXTRACT(EPOCH FROM (a.timefield - b.timefield))) AS "Time Apart" FROM a INNER JOIN b ON (a.id = b.id);

Answer 2

SELECT a.timefield - b.timefield
FROM a 
  INNER JOIN B on (a.id = b.id)

会为您提供间隔数据类型