Question

我有字符串，我试图拆分文本并设置其格式

输入为 67.9200 2 3

输出将为 6 7.9 200

规则

1) split from the right to left based on the digits passed. 

2) when split contains "." then add 1 to it .

3) if anything is remaining will just show in the front.

示例 67.9200 2 3

 1. 3 (digits) -> will take the last 200
 2. 2 (digits) -> will take 7.9 (since it has ".")
 3. 6          -> Remaining will show (6)

任何建议或解决方案将不胜感激

Answer 1

您可以从右开始扫描字符串，并将其继续存储在StringBuilder中，直到捕获到n1（3）个字符为止；每当遇到点时，跳过计数，一旦n1变为零，请添加空格并继续。对n2（2）应用相同的策略，在StringBuilder中拥有最终字符串后，只需反转字符串即可获得输出。这是一个示例程序。

public static void main(String[] args) {
    String str = "67.9200";
    int n1 = 2;
    int n2 = 3;
    StringBuilder sb = new StringBuilder();

    for (int i = str.length() - 1; i >= 0; i--) {
        if (n2 > 0) {
            char c = str.charAt(i);
            sb.append(c);
            if (c != '.') {
                n2--;
                if (n2 == 0) {
                    sb.append(" ");
                }
            }
        } else if (n1 > 0) {
            char c = str.charAt(i);
            sb.append(c);
            if (c != '.') {
                n1--;
                if (n1 == 0) {
                    sb.append(" ");
                }
            }
        } else {
            sb.append(str.charAt(i));
        }
    }

    System.out.println(sb.reverse().toString());
}

这将提供以下输出，

6 7.9 200

根据传递的输入从右向左拆分文本

1 个答案: