我有以下查询:
SELECT
F.IID,
F.E_NUM AS M_E_NUM,
MCI.E_NUM AS MCI_E_NUM,
F.C_NUM AS M_C_NUM,
MCI.C_NUM AS MCI_C_NUM,
F.ET_ID AS M_ET_ID,
EDIE.ET_ID AS ED_INDV_ET_ID,
COUNT(*) OVER (PARTITION BY F.IID) IID_COUNT
FROM FT_T F JOIN CEMEI_T MCI ON F.IID = MCI.IID
JOIN EDE_T EDE ON MCI.E_NUM = EDE.E_NUM
JOIN EDIE_T EDIE ON EDIE.IID = F.IID AND EDIE.ET_ID = EDE.ET_ID
WHERE
F.DEL_F = 'N'
AND MCI.EFF_END_DT IS NULL
AND MCI.TOS = 'BVVB'
AND EDE.PTEND_DT IS NULL
AND EDE.DEL_S = 'N'
AND EDE.CUR_IND = 'A'
AND EDIE.TAR_N = 'Y'
AND F.IID IN
(
SELECT DISTINCT IID
FROM FT_T
WHERE GROUP_ID = 'BG'
AND DEL_F = 'N'
AND (IID, E_NUM) NOT IN
(
SELECT IID, E_NUM FROM CEMEI_T
WHERE TOS = 'BVVB' AND EFF_END_DT IS NULL
)
);
我基本上是从几个表中获取信息,并为它们创建一个平面记录。
一切正常,除了现在我需要找出FT_T
表中是否有两个记录具有相同的IID
并将其显示为结果集的一部分。
我尝试使用分区,但是即使IID
中有2条记录具有相同的FT_T
记录,结果集中的所有行仍返回一个计数。
我最初说我要从几个表中收集信息的原因是由于这样的事实:FT_T
如果没有两个记录可用于同一IID
,则可能没有我需要的所有信息。 ,因此我必须从查询中JOIN
的其他表中检索它们。但是,我需要知道哪个FT_T.IID
在FT_T
中有两条记录(或多于一条)。
答案 0 :(得分:1)
也许您需要计算join
并进行过滤之前的计数:
SELECT . . .
FROM (SELECT F.*,
COUNT(*) OVER (PARTITION BY F.IID) as IID_CNT
FROM FT_T F
) JOIN
CEMEI_T MCI
ON F.IID = MCI.IID JOIN
EDE_T EDE
ON MCI.E_NUM = EDE.E_NUM JOIN
EDIE_T EDIE
ON EDIE.IID = F.IID AND EDIE.ET_ID = EDE.ET_ID
. . .
答案 1 :(得分:0)
这仅仅是评论/观察,但需要格式化
将var data = [{ name: 'Dallas Stars', roster: ['Alexander Radulov', 'Ben Bishop', 'Jamie Benn', 'Tyler Pitlick', 'Miro Heiskanen' ] }, { name: 'Los Angeles Kings', roster: ['Jonathan Quick', 'Jonny Brodzinski', 'Oscar Fantenberg' ] }, { name: 'San Jose Sharks', roster: ['Joe Thornton', 'Brent Burns', 'Joe Pavelski', 'Antti Suomela' ] }, { name: 'Columbus Blue Jackets', roster: ['Sonny Milano', 'Brandon Dubinsky', 'Nick Foligno', 'Pierre-Luc Dubois' ] } ];
var res = data
.map(({name, roster}) =>
roster.map(playerName => ({name, playerName})))
.flat();
console.log(res);
与in(...)
和select distinct
一起使用似乎很复杂,如果某些值为NULL可能会成为问题。我建议您考虑改用EXISTS和NOT EXISTS。例如
not in(...,...)