Question

var arr1 =['Five','Four','Full','Straight','Three','Two','One','Bust']
var arr2 = [{player1-box: "One"},{player2-box: "One"},{player3-box: "Four"},{player1-box: "Three"},{player2-box: "Three"},{player3-box: "Two"},{player1-box: "Five"},{player2-box: "One"},{player3-box: "One"}]

我有两个如上所述的数组。我的要求是比较两个数组，并从第二个数组中获取第一个匹配值。在此示例中，arr1中的值“ FIVE”将匹配第二个数组arr2中第7个索引中的值

意味着我将获得像{player1-box：“ Five”}}这样的键和值？有人可以调查一下并让我知道吗？

谢谢..

Answer 1

如果在arr1中用Array#some找到了一个对象，则可以用Array#find迭代arr2并退出循环。

虽然对象具有不同的键，但是您需要获取用于检查的值。

var arr1 = ['Five', 'Four', 'Full', 'Straight', 'Three', 'Two', 'One', 'Bust'],
    arr2 = [{ "player1-box": "One" }, { "player2-box": "One" }, { "player3-box": "Four" }, { "player1-box": "Three" }, { "player2-box": "Three" }, { "player3-box": "Two" }, { "player1-box": "Five" }, { "player2-box": "One" }, { "player3-box": "One" }],
    result;

arr1.some(v => result = arr2.find(o => Object.values(o).includes(v)));
console.log(result);

没有arrow functions和ES6部分。

var arr1 = ['Five', 'Four', 'Full', 'Straight', 'Three', 'Two', 'One', 'Bust'],
    arr2 = [{ "player1-box": "One" }, { "player2-box": "One" }, { "player3-box": "Four" }, { "player1-box": "Three" }, { "player2-box": "Three" }, { "player3-box": "Two" }, { "player1-box": "Five" }, { "player2-box": "One" }, { "player3-box": "One" }],
    result;

arr1.some(function (v) {
    return arr2.some(function (o)  {
        if (Object.keys(o).some(function (k) { return v === o[k]; })) {
            return result = o;
        }
    });
});
console.log(result);

Answer 2

除了遍历arr1之外，我看不到当前数据设置的任何方式。如果找不到，则将返回arr1的{{1}}中的第一个。

undefined

如果有平局的可能，可以使用var arr1 =['Five','Four','Full','Straight','Three','Two','One','Bust'] var arr2 = [{'player1-box': "One"},{'player2-box': "One"},{'player3-box': "Four"},{'player1-box': "Three"},{'player2-box': "Three"},{'player3-box': "Two"},{'player1-box': "Five"},{'player2-box': "One"},{'player3-box': "One"}] function findFirst(keys, players){ for (key of keys){ let player = players.find(player => Object.values(player).includes(key)) if (player) return player } } let first = findFirst(arr1, arr2) console.log(first)代替filter()并返回一个数组：

find()

如何比较两个数组并从第一个数组中获取第一个匹配对象？

2 个答案: