在我的laravel 5.7应用程序中,我有一个控制器,该控制器具有以下方法,该控制器使用GuzzleHttp \ Client向我的内腔api发送发布请求。
public function insert(Request $request)
{
$domain = Config::get('url.gcr_api'); // gcr_api is defined in app/config/url.php
$url = $domain . "/api/v1/campaign/insert";
$campaign_name = $request->input('campaign_name');
$campaign_provider = $request->input('campaign_provider');
$client = new Client;
$response = $client->request('POST', $url , [
'headers' => [
'X-XSRF-TOKEN' => csrf_token(),
],
'form_params' => [
'name' => $campaign_name,
'bank_id' => $campaign_provider,
]
]
);
$data = json_decode($response->getBody(), true);
return $data;
}
}
这是上述方法调用的lumen api的代码。
public function insert(Request $request) {
try {
$campaign_name = $request->input('campaign_name');
$campaign_provider = $request->input('campaign_provider');
$data = array('name' => $campaign_name, 'bank_id' => $campaign_provider);
DB::table('campaign')->insert($data);
$response = array(
'status' => 'success',
'message' => 'Campaign created successfully',
);
return response()->json($response);
}
catch(Exception $e) {
// When query fails.
$response = array(
'status' => 'failed',
'message' => 'Failed to create campaign',
);
return response()->json($response);
}
}
每次调用laravel应用控制器的insert方法时,我都会收到此错误:
GuzzleHttp \ Exception \ ServerException(500)服务器错误:
POST http://localhost:8000/api/v1/campaign/insert
导致500 Internal Server Error
响应:
我认为该错误与我的内腔api无法获取form_params数据有关,因此我在我的内腔api代码中注释掉了这段代码,错误消失了:
/*$campaign_name = $request->input('campaign_name');
$campaign_provider = $request->input('campaign_provider');
$data = array('name' => $campaign_name, 'bank_id' => $campaign_provider);
DB::table('campaign')->insert($data); */
但是我需要在流明api中获取form_params数据,该怎么做?
答案 0 :(得分:0)
您的假设部分正确,可以访问form_params,但是您尝试获取的form_params与实际参数有所不同:
为了传递参数,请使用以下数组:
'form_params' => [
'name' => $campaign_name,
'bank_id' => $campaign_provider,
]
此数组将使用键“名称”将值设置为$campaign_name
,将$campaign_provider
设置为bank_id
。到目前为止,这段代码没有错。
不过,您可以在API中执行以下操作:
$campaign_name = $request->input('campaign_name');
$campaign_provider = $request->input('campaign_provider');
但是没有键campaign_name
或campaign_provider
,因为它们已更改为name
和bank_id
。因此,如果将其更改为以下内容,则应该可以使用:
$campaign_name = $request->input('name');
$campaign_provider = $request->input('bank_id');