插入信息在Android Studio的sqlite中不起作用进行练习

Question

伙计们，我一直试图在android studio中创建的表ive中插入一些数据，这里是代码。

package database.oxbir.com.databae;

import android.content.ContentValues;
import android.content.Context;
import android.database.SQLException;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;

/**
 * Created by Oxbir on 28/10/2018.
 */

public class DataModelLayer extends SQLiteOpenHelper {
    public static final String DB_NAME = "oxbir";
    public static final int DB_VERSION = 1;
    public static final String TBL_NAME = "users";

    public static final String COL_ID =  "id";
    public static final String COL_NAME =  "name";
    public static final String COL_FAMILY =  "family";
    public static final String COL_AGE =  "age";

    public static final String Query = "CREATE TABLE IF NOT EXISTS " + TBL_NAME + "(" +
            COL_ID + " INTEGER PRIMARY KEY AUTOINCREMENT," +
            COL_NAME + "TEXT," +
            COL_FAMILY + "TEXT," +
            COL_AGE + "INTEGER);";

    Context context;

    public DataModelLayer(Context context) {
        super(context, DB_NAME, null, DB_VERSION);
        this.context = context;
    }

    @Override
    public void onCreate(SQLiteDatabase db) {
        try
        {
            db.execSQL(Query);
        }
        catch (SQLException ex)
        {
            ex.printStackTrace();
        }
    }

    @Override
    public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {

    }

    public long addInfo (String name, String family, int age){
        ContentValues contentValues = new ContentValues();
        contentValues.put(COL_NAME, name);
        contentValues.put(COL_FAMILY, family);
        contentValues.put(COL_AGE, age);

        SQLiteDatabase sqLiteDatabase = this.getWritableDatabase();
        long result = sqLiteDatabase.insert(TBL_NAME, null, contentValues);
        if (result > 0)
        {
            return result;
        }
        else
        {
            return result;
        }
    }
}
package database.oxbir.com.databae;

import android.content.ContentValues;
import android.content.Context;
import android.database.SQLException;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;

/**
 * Created by Oxbir on 28/10/2018.
 */

public class DataModelLayer extends SQLiteOpenHelper {
    public static final String DB_NAME = "oxbir";
    public static final int DB_VERSION = 1;
    public static final String TBL_NAME = "users";

    public static final String COL_ID =  "id";
    public static final String COL_NAME =  "name";
    public static final String COL_FAMILY =  "family";
    public static final String COL_AGE =  "age";

    public static final String Query = "CREATE TABLE IF NOT EXISTS " + TBL_NAME + "(" +
            COL_ID + " INTEGER PRIMARY KEY AUTOINCREMENT," +
            COL_NAME + "TEXT," +
            COL_FAMILY + "TEXT," +
            COL_AGE + "INTEGER);";

    Context context;

    public DataModelLayer(Context context) {
        super(context, DB_NAME, null, DB_VERSION);
        this.context = context;
    }

    @Override
    public void onCreate(SQLiteDatabase db) {
        try
        {
            db.execSQL(Query);
        }
        catch (SQLException ex)
        {
            ex.printStackTrace();
        }
    }

    @Override
    public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {

    }

    public long addInfo (String name, String family, int age){
        ContentValues contentValues = new ContentValues();
        contentValues.put(COL_NAME, name);
        contentValues.put(COL_FAMILY, family);
        contentValues.put(COL_AGE, age);

        SQLiteDatabase sqLiteDatabase = this.getWritableDatabase();
        long result = sqLiteDatabase.insert(TBL_NAME, null, contentValues);
        if (result > 0)
        {
            return result;
        }
        else
        {
            return result;
        }
    }
}

每当我调用此活动时，都会收到id=1消息。

我发现活动没有任何问题，因此应用程序没有崩溃，所以我决定举杯儿插入查询，看是否有什么问题。

据我所知，只要包括在内，就可以购买。

在我的代码中，应用程序崩溃了（临时包含我刚刚敬酒的查询）

任何帮助将不胜感激。

Answer 1

如果粘贴了正确的代码，则表的创建sql中有错误，请更改为：

public static final String Query = "CREATE TABLE IF NOT EXISTS " + TBL_NAME + "(" +
        COL_ID + " INTEGER PRIMARY KEY AUTOINCREMENT," +
        COL_NAME + " TEXT," +
        COL_FAMILY + " TEXT," +
        COL_AGE + " INTEGER);";

我在字段名称和类型之间包括了空格。
现在，先卸载应用程序，然后再次运行。

还可以简化addInfo()方法：

public long addInfo (String name, String family, int age){
    ContentValues contentValues = new ContentValues();
    contentValues.put(COL_NAME, name);
    contentValues.put(COL_FAMILY, family);
    contentValues.put(COL_AGE, age);

    SQLiteDatabase sqLiteDatabase = this.getWritableDatabase();
    long result = sqLiteDatabase.insert(TBL_NAME, null, contentValues);
    sqLiteDatabase.close()
    return result; 
}