Question

我有一个像"abc1abc1"这样的字符串。

我要做的是将字符串的每个数字加粗。我在下面绘制了代码。它通过分离字符串的每个字符并将它们放入数组中来工作。然后，在循环中，如果每个字符都包含一个Int()，则该字符将以粗体显示。

但是，当有两个相同的Int时，就会出现问题。在上面的字符串中，1有2个字符，因此代码只会将第一个字符加粗。

// Bold the numbers
    let fullString = "abc1abc1"
    let characters = Array(fullString)
    let mutableString = NSMutableAttributedString(string: fullString)
    for item in characters {
        let string = String(item)
        let decimalCharacters = CharacterSet.decimalDigits
        let decimalRange = string.rangeOfCharacter(from: decimalCharacters)
        if decimalRange != nil {
            let str = NSString(string: fullString)
            let range = str.range(of: string)
            mutableString.addAttribute(NSAttributedStringKey.foregroundColor, value: UIFont.systemFont(ofSize: 18, weight: .heavy), range: range)
        }
    }
    instructionsLabel.attributedText = mutableString

// characters = ["a", "b", "c", "1", "a", "b", "c", "1"]
// range of ints returns {3, 1} and {3, 1}
// range of ints SHOULD return {3, 1} and {7, 1}

Answer 1

尝试一下：

let fullString = "abc1abc1"
let range = NSRange(location: 0, length: (fullString as NSString).length)
let mutableString = NSMutableAttributedString(string: fullString)
let regex = try! NSRegularExpression(pattern: "[0-9]")
let matches = regex.matches(in: fullString, range: range)

for match in matches {
    mutableString.addAttributes([.font: UIFont.systemFont(ofSize: 18, weight: .heavy)], range: match.range)
}

instructionsLabel.attributedText = mutableString

字符串复制中字母的范围位置

1 个答案: