我想创建一个查询,如果DATEDIFF(so_date,actual_delivery)= 3,它将显示单词“ Passed”,否则显示“ Failed”。有人可以帮我吗?
<?php
$hostname="localhost";
$username="root";
$password="";
$db = "csl_otd";
$dbh = new PDO("mysql:host=$hostname;dbname=$db", $username, $password);
foreach($dbh->query('SELECT so_date,
actual_delivery,
case when DATEDIFF(so_date, actual_delivery) = 3
then "Passed"
else "Failed"
end as status
FROM sales_order
LEFT JOIN dar ON sales_order.dar_numberr = dar.dar_number
WHERE DATEDIFF(so_date, actual_delivery) < 10') as $row) {
echo "<tr>";
echo "<td>" . $row['so_date'] . "</td>";
echo "<td>" . $row['actual_delivery'] . "</td>";
echo "<td>" . $row['DATEDIFF(so_date,actual_delivery)'] . "</td>";
echo "<td>" . $row['status'] . "</td>";
echo "</tr>";
}
?>
</tbody></table>
输出
Date Difference | Status
2 | Passed
4 | Failed
答案 0 :(得分:0)
用例何时
SELECT so_date,actual_delivery,
DATEDIFF(so_date,actual_delivery) Date_Difference,
case when DATEDIFF(so_date,actual_delivery) = 3
then "Passed"
else "Failed" end Status
FROM sales_order
LEFT JOIN dar
ON sales_order.dar_numberr=dar.dar_number
WHERE DATEDIFF(so_date,actual_delivery)<10
或者如果您使用过,也可以使用(但是校正很少)
SELECT so_date,actual_delivery,DATEDIFF(so_date,actual_delivery),
if ( DATEDIFF(so_date,actual_delivery) = 3
,'Passed','Failed') status
FROM sales_order
LEFT JOIN dar
ON sales_order.dar_numberr=dar.dar_number
WHERE DATEDIFF(so_date,actual_delivery)<10