这是我的JavaScript代码:
$("#bot1Selected").attr("card-value", botPick.value + botPick.suit.substring(0, 1));
$("#bot1Selected").css("background-image", "url('images/cards/" + checkValue(botPick.value) + botPick.suit.substring(0, 1) + ".png')");
$("#player1Selected").attr("card-value", playerDisplay);
$("#player1Selected").css("background-image", "url('images/cards/" + checkValue(playerDisplay.slice(0, -1)) + playerDisplay[playerDisplay.length - 1] + ".png')");
if (playerVal.value > botPick.value) {
//sleep(500);
alert("Your Card is Higher");
} else {
//sleep(500);
alert("Bot's Card is Higher");
}
if (playerVal.value > botPick.value) {
endTurn(playerDiscard, [playerVal, botPick]);
} else {
endTurn(bot1Discard, [playerVal, botPick]);
}
$("#playerDiscard").text(playerDiscard.length);
$("#playerDraw").text(player.length);
为什么我的警报发生在我的图像反映在页面上之前?
答案 0 :(得分:0)
jQuery.css()
函数是异步的。它会立即返回,因此加载图像时不会返回。
创建一个“虚拟”图像以预加载它,并使用onload
事件来确定何时加载该图像。
jQuery(document).ready(function() {
var imgUrl = "https://via.placeholder.com/350x150";
var $img = $("<img />");
$img.on("load", function() {
$("#yourImage").css("background-image", "url("+ imgUrl +")");
alert("image is loaded");
});
$img.attr("src", imgUrl);
});