Flask-sqlalchemy-棉花糖嵌套模式不起作用

时间:2018-11-09 10:32:45

标签: flask flask-sqlalchemy marshmallow

基本上我想做的是,将2个表“ users”和“ company”联接起来,并向用户提供其相关的公司详细信息。

这是用户模型:

class User(db.Model):
__tablename__ = 'user'
id = db.Column(db.Integer, primary_key=True, autoincrement=True)
firstname = db.Column(db.String(10), nullable=False)
lastname = db.Column(db.String(25), nullable=False)
username = db.Column(db.String(250), nullable=False)
email = db.Column(db.String(100), nullable=False)
password = db.Column(db.String(250), nullable=False)
isPasswordReset = db.Column(db.Boolean, nullable=False)
companyId = db.Column(db.Integer, db.ForeignKey(
    'company.id'), nullable=True)

这是架构

class UserSchema(ma.Schema):
id = fields.Integer()
firstname = fields.String(required=True)
lastname = fields.String(required=True)
username = fields.String(required=True)
email = fields.String(required=True)
password = fields.String(required=True)
isPasswordReset = fields.Boolean(required=True)
companyId = fields.Integer()
company_name = fields.Nested(CompanySchema)

这是公司模式:

class Company(db.Model):
__tablename__ = 'company'
id = db.Column(db.Integer, primary_key=True, autoincrement=True)
companyName = db.Column(db.String(100), nullable=True)
companyCode = db.Column(db.String(20), nullable=True)
companyTheme = db.Column(db.String(300), nullable=True)

这是公司架构:

class CompanySchema(ma.Schema):
id = fields.Integer()
companyName = fields.String(required=True)
companyCode = fields.String(required=True)
companyTheme = fields.String(required=True)

这是resource-user.py:

users_schema = UserSchema(many=True)
user_schema = UserSchema()

class UsersResource(Resource):
def get(self):
users = db.session.query(User.firstname, Company.companyName).join(
Company, User.companyId == Company.id).all()
if users:
results = users_schema.dump(users).data
return {'status': 'success', 'message': json.dumps(results, default=str)}, 200

这是我得到的输出:

  

{       “ status”:“成功”,       “消息”:“ [{\”名字\“:\” abc \“},{\”名字\“:\” xyz \“}]”   }

仅显示用户表,而不显示公司表。我已经花了几个小时来学习大量的教程和资料。但仍然无法解决。我是flask和sqlalchemy的新手。请问有人知道如何纠正这个问题吗?

1 个答案:

答案 0 :(得分:3)

首先,您需要在sqlalchemy模型中声明关系对象:

class User(db.Model):
    __tablename__ = 'user'
    id = db.Column(db.Integer, primary_key=True, autoincrement=True)
    firstname = db.Column(db.String(10), nullable=False)
    lastname = db.Column(db.String(25), nullable=False)
    username = db.Column(db.String(250), nullable=False)
    email = db.Column(db.String(100), nullable=False)
    password = db.Column(db.String(250), nullable=False)
    isPasswordReset = db.Column(db.Boolean, nullable=False)
    companyId = db.Column(db.Integer, db.ForeignKey(
                         'company.id'), nullable=True)
    company = db.relationship("Company", backref="parents")  # <--

然后在用户架构的声明字段中代表该对象:

class UserSchema(ma.Schema):
    id = fields.Integer()
    firstname = fields.String(required=True)
    lastname = fields.String(required=True)
    username = fields.String(required=True)
    email = fields.String(required=True)
    password = fields.String(required=True)
    isPasswordReset = fields.Boolean(required=True)
    companyId = fields.Integer()
    company = fields.Nested(CompanySchema) # <-- 

请注意,字段名称必须相同(或者您可以使用attribute参数)。

查询时,您可以轻松做到:

user_schema = UserSchema()
users = User.query.all()
results = users_schema.dump(users).data
return {'status': 'success', 'message': json.dumps(results, default=str)}, 200

(或return users_schema.dump(users)用于测试)

毕竟您应该获得如下输出:

{
id: 'something',
firstname: 'something',
lastname: 'something',
username: 'something',
email: 'something',
password: 'something',
isPasswordReset: 'something',
company : {
           id: 'something',
           companyName: 'something',
           companyCode: 'something',
           companyTheme: 'something',
          }
}

这可以满足您的需求吗?