如何将参数用于POST请求和GET响应?我有两个Model类。每个都有一个电话变量。如何发布而不会崩溃?如何在json
中打印logcat
文件?
依赖项:
implementation 'com.mcxiaoke.volley:library:1.0.19'
implementation 'com.google.code.gson:gson:2.8.5'
自定义Gson:
public class GsonRequest<T> extends Request<T> {
private Gson gson = new Gson();
private Class<T> clazz;
private Map<String, String> headers;
private Map<String, String> params;
private Listener<T> listener;
/**
* Make a GET request and return a parsed object from JSON.
*
* @param url URL of the request to make
* @param clazz Relevant class object, for Gson's reflection
* @param params Map of request headers
*/
public GsonRequest(int method, String url, Class<T> clazz, Map<String, String> params, Listener<T> listener, ErrorListener errorListener) {
super(method, url, errorListener);
this.clazz = clazz;
this.headers = null;
this.params = params;
this.listener = listener;
gson = new Gson();
}
@Override
public Map<String, String> getHeaders() throws AuthFailureError {
return headers != null ? headers : super.getHeaders();
}
@Override
protected Map<String, String> getParams() throws AuthFailureError {
return params;
}
@Override
protected void deliverResponse(T response) {
listener.onResponse(response);
}
@Override
protected Response<T> parseNetworkResponse(NetworkResponse response) {
try {
String json = new String(response.data,
HttpHeaderParser.parseCharset(response.headers));
return Response.success(
gson.fromJson(json, clazz),
HttpHeaderParser.parseCacheHeaders(response));
} catch (UnsupportedEncodingException | JsonSyntaxException e) {
return Response.error(new ParseError(e));
}
}
}
请求:
RequestQueue requestQueue = Volley.newRequestQueue(getApplicationContext());
GsonRequest<Model> gsonRequest = new GsonRequest<Model>(Request.Method.POST, url, Model.class, null, new Response.Listener<Model>() {
@Override
public void onResponse(Model response) {
Toast.makeText(getApplicationContext(), "success" + " " + response, Toast.LENGTH_LONG).show();
Log.d(TAG, response.toString());
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
textView.setText(error.toString());
Toast.makeText(getApplicationContext(), "error" + " " + error, Toast.LENGTH_LONG).show();
Log.d(TAG, error.toString());
}
});
requestQueue.add(gsonRequest);
}
主要型号:
public class Model {
private Business business;
private Contacts contacts;
public Model(Business business, Contacts contacts) {
this.business = business;
this.contacts = contacts;
}
商业模式:
public class Business {
private String created_by;
private String business_name;
private String phone;
private String business_description;
private String address;
private String customer_name;
private String businessEmail;
private String business_type;
public Business(String created_by, String business_name, String phone, String business_description, String address,
String customer_name, String businessEmail, String business_type) {
this.created_by = created_by;
this.business_name = business_name;
this.phone = phone;
this.business_description = business_description;
this.address = address;
this.customer_name = customer_name;
this.businessEmail = businessEmail;
this.business_type = business_type;
}
联系方式:
public class Contacts {
private String lastName;
private String phone;
private String email;
private String firstName;
public Contacts(String lastName, String phone, String email, String firstName) {
this.lastName = lastName;
this.phone = phone;
this.email = email;
this.firstName = firstName;
}
Json文件:
{ "business": {
"address": "xxx",
"business_description": "xx",
"businessEmail": "xxx@gmail.com",
"business_name": "xxx",
"phone":"1234567890",
"business_type": "xx",
"created_by": "xxx",
"customer_name": "xxx"
},
"contacts": [ {
"email": "yyy@gmail.com",
"firstName": "yyy",
"lastName": "yyy", "phone": "6544324569"
} ]
}
答案 0 :(得分:1)
我认为您已经解决了。不知道在哪里以及为什么很难将参数传递给请求。
根据这里发布的示例JSON文件,我建议对您的Model.java
进行一些改动。
import java.util.List;
import java.util.ArrayList;
public class Model {
private Business business;
private List<Contacts> contacts = new ArrayList<>(); /* changes */
public Model(Business business, List<Contacts> contacts) {
this.business = business;
this.contacts.addAll(contacts); /* changes */
}
}
“活动”或“片段”中的现在准备数据并将其传递给请求。
List<Contacts> contacts = new ArrayList<>();
Contacts con1 = new Contacts(/* required parameters */);
contacts.add(con1);
Contacts con2 = new Contacts(/* required parameters */);
contacts.add(con2);
// add as many as you want
Business business = new Business(/* required parameters */);
// add both parameters to Model class
Model data = new Model(business, contacts);
// and finally pass it to request parameter
RequestQueue requestQueue = Volley.newRequestQueue(getApplicationContext());
GsonRequest<Model> gsonRequest = new GsonRequest<Model>(
Request.Method.POST,
url,
data, /* PLEASE NOTICE THE DIFFERENCE HERE: use data of type Model instead of Model.class */
null,
new Response.Listener<Model>() {
@Override
public void onResponse(Model response) {
Toast.makeText(getApplicationContext(), "success" + " " + response, Toast.LENGTH_LONG).show();
Log.d(TAG, response.toString());
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
textView.setText(error.toString());
Toast.makeText(getApplicationContext(), "error" + " " + error, Toast.LENGTH_LONG).show();
Log.d(TAG, error.toString());
}
}
);
requestQueue.add(gsonRequest);
在这里,您需要更改GsonRequest<Model>()
构造函数的第3个参数。