Question

我有一个查询：

SELECT u.user_id, f.eye_color, c.rating
FROM
user u LEFT JOIN connection c ON u.user_id = c.connection_user_id,
   user_field f,
   search s
WHERE
    s.search_id = 1 AND
    u.user_id = f.user_id AND
    s.user_id != u.user_id
GROUP BY
    u.user_id;

这是它显示的错误

错误代码：1055。SELECT列表的表达式＃51不在GROUP BY子句中，并且包含非聚合列'sos.c.rating'，该列在功能上不依赖于GROUP BY子句中的列；这与sql_mode = only_full_group_by
不兼容

Answer 1

您可以在下面尝试

您将显式联接和隐式联接混合在一起，并且GROUP BY是不必要的，因为您不聚合任何列

SELECT u.user_id, f.eye_color, c.rating
FROM
user u LEFT JOIN connection c ON u.user_id = c.connection_user_id,
   left join user_field f on u.user_id = f.user_id
   left join search s on s.user_id != u.user_id
WHERE
    s.search_id = 1

Answer 2

您必须在分组依据

中添加所有可更改的列

选择u.user_id，f.eye_color，c.rating

从

用户u左联接连接c ON u.user_id = c.connection_user_id，

user_field f，

搜索

在哪里

11
</td>
<td class="no-wrap currency-name" data-sort="TRON">
<img data-src="https://s2.coinmarketcap.com/static/img/coins/16x16/1958.png" class="logo-sprite lazyload" alt="TRON" src="data:image/gif;base64,R0lGODlhAQABAAAAACH5BAEKAAEALAAAAAABAAEAAAICTAEAOw==" height="16" width="16">

组别

s.search_id = 1 AND

u.user_id = f.user_id AND

s.user_id != u.user_id

如何合并4个表并按user_id分组

2 个答案: