Question

当我选择他时，他只是得到值名称Ahmad-如何获得值ahmad zakaria？

HTML：

<select name="kd_produk" id="family">
    <option value="one"
    data-name= "Ahmad Zakaria"
    data-wife= "My wife">number one</option>
</select>

JS

$("select#family").change(function(){
var name1 = $('select#family').find(':selected').data('name1');
var wife1 = $('select#family').find(':selected').data('wife1');

Answer 1

标记中没有选择元素wife1的属性name1或<option />。

尝试从传递给1方法的每个键字符串中删除.data()：

var name = $('select#family').find(':selected').data('name');
var wife = $('select#family').find(':selected').data('wife');

这将确保按预期方式检索与属性data-wife和data-name对应的值：

var name = $('select#family').find(':selected').data('name');
var wife = $('select#family').find(':selected').data('wife');

console.log('data-name of selected:', name)
console.log('data-wife of selected:', wife)

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
<select name="kd_produk" id="family">
    <option value="one"
    data-name= "Ahmad Zakaria"
    data-wife= "My wife">number one</option>
</select>

如何获取所选选项的数据属性值？

1 个答案: