如何使laravel应用程序在Nginx服务器上工作？

Question

我刚刚使用LEMP堆栈和Nginx服务器在DigitalOcean上部署了Laravel应用程序。

但是，当我导航到服务器IP地址时，出现403 Forbidden错误。然后，当我转到xxx.xx.xxx.xx / public时，即使我已经将root设置为我的公用文件夹，也可以正确看到我的主页。另外，当我单击主页上的任何链接时，都会显示404未找到。

这是我的etc / nginx / sites-available / default：

我在做什么错？请不要将我的问题标记为重复，因为我看到大多数相似的话题都忘记了将Index.php添加到其索引列表中，或者忘记将其根链接到其公用文件夹，但是我都做得很好。 >

我的配置文件：

# Default server configuration 
#
server {
    listen 80 default_server;
    listen [::]:80 default_server; 

    # SSL configuration
    #
    # listen 443 ssl default_server;
    # listen [::]:443 ssl default_server;
    #
    # Note: You should disable gzip for SSL traffic.
    # See: https://bugs.debian.org/773332
    #
    # Read up on ssl_ciphers to ensure a secure configuration.
    # See: https://bugs.debian.org/765782
    #
    # Self signed certs generated by the ssl-cert package
    # Don't use them in a production server!
    #
    # include snippets/snakeoil.conf; 

    root /var/www/html/public/; 

    # Add index.php to the list if you are using PHP
    index index.php index.html index.htm index.nginx-debian.html; 

    server_name 159.65.192.29; 

    location / {
        # First attempt to serve request as file, then
        # as directory, then fall back to displaying a 404.
        try_files $uri $uri/ /index.php?$query_string; 
    } 

    # pass PHP scripts to FastCGI server
    #
    location ~ \.php$ {
        include snippets/fastcgi-php.conf;
    #
    #   # With php-fpm (or other unix sockets):
        fastcgi_pass unix:/var/run/php/php7.0-fpm.sock;
    #   # With php-cgi (or other tcp sockets):
    #   fastcgi_pass 127.0.0.1:9000; 
    }
}

Answer 1

尝试在项目的根目录下将server.php名称更改为index.php，并使用以下内容创建一个nginx.conf文件：

# nginx configuration location ~* (\.css|\.mp4|\.woff|\.js|\.png|\.jpg|\.gif|robots\.txt)$ { } location ~ /public/ { } location / { if (!-e $request_filename){ rewrite ^/(.*)/$ /$1 redirect; } if (!-e $request_filename){ rewrite ^(.*)$ /index.php break; } if (!-e $request_filename){ rewrite ^/(css|js|images|favicon|fonts|videos|storage)/(.*)$ /public/$1/$2 break; } }

Answer 2

我在服务器上使用它。测试一下：

while ($row = mysqli_fetch_assoc($result)){
    $info[$row['converternumber']][$row['zonenumber']][] = $row['codeid'];
}