Question

问题在于，当您输入40时，它会下降到35，如果您输入数字46、48、57、78等也会发生这种情况。

def Marking():
    Mark=int(input("What mark did you get (between 0 - 100)?: "))
    while Mark >100:
        Mark=int(input("What mark did you get (between 0 - 100)?: "))

    days_late=int(input("How many days late was it submited (between 0 - 12)? :"))
    while days_late >12:
        days_late=int(input("How many days late was it submited (between 0 - 12)? :"))

    while days_late != 0:
        Mark = Mark - 5
        days_late = days_late -1
        print(days_late, "Final mark is =", Mark)

        if Mark <=40:
            break       #The problem is somewhere here i think 

    while days_late == 0:
        print("your final mark is: ", Mark)
        break



    while 0 <= Mark <=40:
            print("your mark is:", Mark)
            break

What mark did you get (between 0 - 100)?: 40

How many days late was it submited (between 0 - 12)? :5

4 Final mark is = 35         ########this should be capped at 40 and no lower

A. Marking
E. Extend
X. Exit Program
Enter an Option: A,E or X:

Answer 1

if Mark <=40: ... break会立即中断循环，如果您输入的数值等于或大于40（加上减去的5），那么最多只能打印40张（例如，从45开始），然后减去5，然后打破循环）。

不相关，但是如果输入负数days_late，则有一个无限循环while days_late != 0，因此建议您先设置while days_late > 0，然后再选择mark = mark - 5。除非您真的想限制标记值可以下降的程度，否则根本不需要break语句。

然后丢失最后两个while循环，请改用if。而且我认为您不需要两次打印相同的标记值

总而言之，应该确实是这样

while days_late > 0:
    mark -= 5
    days_late -= 1
    print(days_late, "Current mark is =", mark)

print("your final mark is: ", mark)

如果您需要将最大标记限制为40，则可以在减去5之后执行此操作

mark = max(mark, 40)

Answer 2

是的，问题在这里：

if Mark <=40:
    break       #The problem is somewhere here i think

您离开循环知道标记可能在35-40范围内的任何位置。请注意，只有在获得5分后，您才可以检查该值。然后，您break的价值将您带入40。

在离开前进行调整：

if Mark <=40:
    Mark = 40
    break

如果，您的程序将会更干净

只有在最终标记最终之后才打印最终标记；不要每次都循环打印。
更好的是，不要循环播放。只需将扣减计算为5*days_late，然后将其减去，然后在需要时将其设置回40。
删除最后的while-只需到达此位置，您就可以知道已执行了罚款。这是您打印最终成绩的地方。

Answer 3

递减完成后，您正在崩溃。在40个极限过滤器之后递减如何？

while days_late != 0:

    print(days_late, "Final mark is =", Mark)

    if Mark <=40:
        break       

    Mark = Mark - 5

    days_late = days_late - 1

输出：

What mark did you get (between 0 - 100)?: 50
How many days late was it submited (between 0 - 12)? :12
(12, 'Final mark is =', 50)
(11, 'Final mark is =', 45)
(10, 'Final mark is =', 40)
('your mark is:', 40)

X-5 = Y。当达到40时关闭程序

3 个答案: