从文件下面的文本：
current_build: 22
previous_build: 55
我只是尝试grep current_build的数字值。
按照以下命令运行
grep -o -E '[0-9]+' textfile
输出是两个数字，如下所示
22
55
我如何只grep值22
答案 0 :(得分：1)
使用GNU grep：
grep -Po 'current_build: \K.*' file
\K：删除\ K之前的匹配部分
输出：
22
答案 1 :(得分：1)
我将使用#include <iostream>
#include <time.h>
bool equalTMs(tm& tm1, tm& tm2);
void printTM(tm& myTM);
int main()
{
tm myTM;
time_t datetime = 1530173696;
//datetime = 1530176399; // to check the time_t value of 8:59 AM
gmtime_s(&myTM, &datetime);
myTM.tm_sec = 0;
myTM.tm_min = 0;
time_t myTime_T = mktime(&myTM);
tm sanityCheckTM;
time_t roundedDownToNearestHour = 1530172800;
gmtime_s(&sanityCheckTM, &roundedDownToNearestHour);
time_t sanityCheckTimeT = mktime(&sanityCheckTM);
std::cout << "datetime: " << datetime << std::endl;
std::cout << "myTime_T: " << myTime_T << std::endl;
std::cout << std::endl;
std::cout << "roundedDownToNearestHour: " << roundedDownToNearestHour << std::endl;
std::cout << "sanityCheckTimeT: " << sanityCheckTimeT << std::endl;
std::cout << std::endl;
std::cout << "myTM and sanityCheckTM equal? " << (equalTMs(myTM, sanityCheckTM) ? "true" : "false") << std::endl;
std::cout << "\nmyTM:-\n\n";
printTM(myTM);
std::cout << "\nsanityCheckTM:-\n\n";
printTM(sanityCheckTM);
std::cout << "\n";
time_t _time_t = 1530158400;
tm _tm;
gmtime_s(&_tm, &_time_t);
std::cout << "_time_t: " << _time_t << std::endl;
std::cout << "_tm and sanityCheckTM equal? " << (equalTMs(_tm, sanityCheckTM) ? "true" : "false") << std::endl;
std::cout << "\n_tm:-\n\n";
printTM(_tm);
}
void printTM(tm& myTM)
{
std::cout << "tm_sec: " << myTM.tm_sec << std::endl;
std::cout << "tm_min: " << myTM.tm_min << std::endl;
std::cout << "tm_hour: " << myTM.tm_hour << std::endl;
std::cout << "tm_mday: " << myTM.tm_mday << std::endl;
std::cout << "tm_mon: " << myTM.tm_mon << std::endl;
std::cout << "tm_year: " << myTM.tm_year << std::endl;
std::cout << "tm_wday: " << myTM.tm_wday << std::endl;
std::cout << "tm_yday: " << myTM.tm_yday << std::endl;
std::cout << "tm_isdst: " << myTM.tm_isdst << std::endl;
}
bool equalTMs(tm& tm1, tm& tm2)
{
return (tm1.tm_sec == tm2.tm_sec)
&& (tm1.tm_min == tm2.tm_min)
&& (tm1.tm_hour == tm2.tm_hour)
&& (tm1.tm_mday == tm2.tm_mday)
&& (tm1.tm_mon == tm2.tm_mon)
&& (tm1.tm_year == tm2.tm_year)
&& (tm1.tm_wday == tm2.tm_wday)
&& (tm1.tm_yday == tm2.tm_yday)
&& (tm1.tm_isdst == tm2.tm_isdst);
}
，因为它与grep awk相反，后者仅适用于GNU grep：
-o awk '/current_build/{print $NF}' file
将输入分为个字段。默认的字段分隔符是空白字符的序列。 awk是字段数，NF是最后一个字段。
答案 2 :(得分：0)
仅在行首打印与current_build匹配的行，并在最后一个空格之后显示部分：
sed -n 's/current_build:.* //p' file