Question

我想将此switch语句转换为if / else和if / then语句。我的Switch语句是：

char option;
printf("Choose your option : ");
scanf("%c",&option);

switch(option){
    case 'a':
    case 'A': a = 20 + 10 ;
        printf("Addition process result:%d",a);
        break;
    case 'b':
    case 'B': a = 20 - 10 ;
        printf("Subtraction process result:%d",a);
        break;
    case 'c':
    case 'C': a = 20 * 10 ;
        printf("Multiplication process result:%d",a);
        break;
    case 'd':
    case 'D': a = 20 + 10 ;
        printf("Division process result:%d",a);
        break;
    default:
        printf("Invalid option");
    }

Answer 1

您只是这样做：

if(option == 'a' || option == 'A') {
    // do whatever
}
else if (option == 'b' || option == 'B') {
    // do whatever
}

...如果不是，则为其他

然后对于“无效选项”，您只有一个else {}。如果第一个if或随后的else的任何一个if的评估结果为true，则将跳过所有其他if。

Answer 2

像这样：

#include <stdio.h>

int main() {
    char option;
    printf("Choose your option : ");
    scanf("%c",&option);

    if (option == 'a' || option == 'A') {
        int a = 20 + 10;
        printf("Addition process result:%d", a);
    } else if (option == 'b' || option == 'A') {
        int a = 20 - 10;
        printf("Subtraction process result:%d", a);
    } else if (option == 'c' || option == 'C') {
        int a = 20 * 10;
        printf("Multiplication process result:%d", a);
    } else if (option == 'd' || option == 'D') {
        int a = 20 + 10;
        printf("Division process result:%d", a);
    } else {
        printf("Invalid option");
    }
    return 0;
}

将Switch语句转换为if / then和if / else语句

2 个答案: