我有一个带有以下文件的Spring MVC项目:
/src/main/webapp/WEB-INF/web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app>
<display-name>Archetype Created Web Application</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/appconfig-root.xml</param-value>
</context-param>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value></param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
</web-app>
和2个配置文件:
/src/main/webapp/WEB-INF/appconfig-root.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns="http://www.springframework.org/schema/beans"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<import resource="appconfig-mvc.xml"/>
<context:component-scan base-package="yc.servlets"/>
<!--<context:property-placeholder location="classpath:application.properties"/>-->
</beans>
/src/main/webapp/WEB-INF/appconfig-mvc.xml
<beans xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<mvc:annotation-driven/>
<mvc:resources mapping="/resources/**" location="/resources/"/>
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/jsp/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
还有包含我的控制器的类:
package yc.servlets;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
@Controller
public class TestPage {
@RequestMapping(value = "/hello_there", method = RequestMethod.GET)
public String hello() {
return "hello";
}
}
我认为这足以使Spring MVC正常工作,但是当我在浏览器中输入localhost:8888
时,会出现404
错误。
localhost:8888/hello_there
也会出现404
错误。
答案 0 :(得分:2)
嗨,您正在控制器中返回“ hello”,它将找到hello.jsp 如果找不到,则会抛出404 http错误
在配置InternalViewResolver时:
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/jsp/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
它试图在/WEB-INF/jsp/hello.jsp中查找,因此当您在控制器中返回字符串“ hello”时:
@RequestMapping(value = "/hello_there", method = RequestMethod.GET)
public String hello() {
return "hello";
}
它将在“ hello”中添加后缀“ .jsp”,并且将尝试找到“ hello.jsp”,因为找不到它会抛出404
您可以从@Controller更改为@RestController,它隐式添加了@ResponseBody批注,并查看其是否在响应中返回“ hello”
如果这还无济于事,您可以更改:
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
对此:
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
如果仍然可以正常工作,请尝试以下步骤:
尝试这样的网址:
localhost:8080/yourApplicationName/hello_there
默认conext-path此处是您的应用名称 如果您转到TOMCAT_HOME / webapps /
您会发现根文件夹中没有您的应用程序
所以这就是为什么本地主机无法找到它的原因:8080 /...
您可以通过两种方式解决此问题:
1.Find your application deployed and copy to root folder in
TOMCAT_HOME/webapps/ROOT
2.See the name of your application in TOMCAT_HOME/webapps/
and call url : localhost:8080/yourAppName/hello_world
谢谢
答案 1 :(得分:0)
我已经在此问题上花费了5多个小时,并证明以下解决方法是成功的。
首先,我更改了/WEB_INF/web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app>
<display-name> Spring version </display-name>
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/mvc-dispatcher-servlet.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
</web-app>
现在,我只有一个文件mvc-servlet-dispatcher.xml
,而不是2个配置文件:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="yc.servlets" />
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/jsp/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
通过这些更改,它可以工作。