Question

我在匹配nodeValue和$property的{{1}}时遇到了一些麻烦。它实际上必须顺利进行，但我在某个地方犯了错误。我想不通。

$value

数据包含在foreach ($links as $getContent){ $getContentData = pageContent($getContent); $getRouteData = new \DOMXPath($getContentData); $sendtoDatabase = [ 'region' => '関西', 'photo' => $images, 'building_name' => '', 'price' => '', 'old_price' => '', 'extend' => '', 'address' => '', 'total_house' => '', 'rooms' => '', 'cons_finish' => '', 'entry' => '', 'balcony' => '', 'company_name' => '', 'date_update' => '毎週月曜日更新', ]; $tableth = $getRouteData->query("//table[@class='outline']/tr/th"); foreach ($tableth as $getth){ $property[] = trim($getth->nodeValue); } $tabletd = $getRouteData->query("//table[@class='outline']/tr/td"); foreach ($tabletd as $gettd){ $value[] = trim($gettd->nodeValue); } switch ($property) { case '物件名': $sendtoDatabase['building_name'] = $value; break; case '販売価格': $sendtoDatabase['price'] = $value; break; case '専有床面積': $sendtoDatabase['extend'] = $value; break; case '所在地': $sendtoDatabase['address'] = $value; break; case '総戸数': $sendtoDatabase['total_house'] = $value; break; case '間取り': $sendtoDatabase['rooms'] = $value; break; case '竣工日': $sendtoDatabase['cons_finish'] = $value; break; case '管理形態': $sendtoDatabase['company_name'] = $value; break; case '入居開始日': $sendtoDatabase['entry'] = $value; break; case 'バルコニー面積': $sendtoDatabase['balcony'] = $value; break; default: break; } }和$property中。没问题，我检查了一下。只是无法将其传递给$value进行匹配。知道为什么会这样。

Answer 1

我建议您再创建一个空变量$new_variable = [];（这会将变量$ new_variable定义为数组。您也可以像这样使它 $new_variable = array();）在您第一次foreach循环之前（在此处发布代码的开头）。

在您的switch之后，像这样填充$new_variable（请举例：

switch ($property) {
            case '物件名':
                $sendtoDatabase['building_name'] = $value;
                break;
            case '販売価格':
                $sendtoDatabase['price'] = $value;
                break;
            case '専有床面積':
                $sendtoDatabase['extend'] = $value;
                break;
            case '所在地':
                $sendtoDatabase['address'] = $value;
                break;
            case '総戸数':
                $sendtoDatabase['total_house'] = $value;
                break;
            case '間取り':
                $sendtoDatabase['rooms'] = $value;
                break;
            case '竣工日':
                $sendtoDatabase['cons_finish'] = $value;
                break;
            case '管理形態':
                $sendtoDatabase['company_name'] = $value;
                break;
            case '入居開始日':
                $sendtoDatabase['entry'] = $value;
                break;
            case 'バルコニー面積':
                $sendtoDatabase['balcony'] = $value;
                break;
            default:
                break;
        }

  //right here BEFORE you close the foreach loop fill $new_variable 
 //with the new value like this
$new_variable[] = $sendtoDatabase;//the '[]' brackets means that each 
//$sendtoDatabase will be inserted into $new_variable[0], then 
//$new_variable[1], and so on untill the last foreach loop

现在foreach()结束之后，执行一段这样的代码

foreach($new_variable as $value){
   //add each $value into the database. this will take each looped foreach and 
  //switch you used before and add them one by one to the database
}

如果您有任何其他问题，我希望这会有所帮助：D我将尽我所能帮助您！

将nodeValue与Switch Case匹配

1 个答案: