Question

[编辑：我固定了两对和满满的房子，但是我的最终成绩是没有对，并且显示出最高的价值，根本没有触发]

我正在从事一个玩骰子扑克游戏的项目。除了骰子滚动两对时，我已经完成了所有“计分”工作。[编辑：两对固定]说是满屋子。

以下是说明：

在本实验中，您将编写一个玩扑克骰子游戏的Java程序。在此游戏中，掷出五个骰子，就好像它们是纸牌一样得分。游戏经历两个单独的阶段。在第一阶段，骰子的“手”被呈现给玩家。然后，玩家选择他想要保留的骰子和他想要重新掷骰子的骰子。一旦决定完成，将重新标记玩家标记为重新投掷的所有骰子，并显示骰子的最终“手”。然后应根据扑克骰子的规则（如下所示）对手进行得分，并将结果显示在屏幕上。

以下是评分规则：

这是我的评分方法代码：

private static String getResult(int[] dice) {
    int i = 0;

    String results = "";

    int endResultsCheck = 0;

    int[] count = getCounts(dice);

    // Checks for 5 of a kind
    while (i < count.length) {
        if (count[i] == 5) {
            results = "Five of a kind!";
            endResultsCheck = 7;
        }
        i++;
    }

    // Checks for four of a kind
    i = 0;
    if (endResultsCheck != 7) {
        while (i < count.length) {
            if (count[i] == 4) {
                results = "Four of a kind!";
                endResultsCheck = 6;
            }
            i++;
        }
    }
    if (endResultsCheck < 6) {
        // Checks for full house
        i = 0;
        int check = 0;
        while (i < count.length) {
            if (count[i] == 3) {
                check++;
            }
            if (count[i] == 2) {
                check++;
            }
            i++;
        }
        if (check == 2) {
            results = "Full house!";
            endResultsCheck = 5;
        }
    }
    if (endResultsCheck < 5) {
        // Checks for three of a kind
        i = 0;
        while (i < count.length) {
            if (count[i] == 3) {
                results = "Three of a kind!";
                endResultsCheck = 4;
            }
            i++;
        }
    }
    if (endResultsCheck < 4) {
        // Checks for two pairs
        i = 0;
        int check = 0;
        while (i < count.length) {
            if (count[i] == 2) {
                check++;
            }
            i++;
        }
        if (check == 2) {
            results = "Two pairs!";
            endResultsCheck = 3;
        }
    }
    if (endResultsCheck < 3) {
        i = 0;
        while (i < count.length) {
            if (count[i] == 2) {
                results = "One pair!";
            }
            i++;
        }
        endResultsCheck = 2;
    }
    if (endResultsCheck == 0) {
        i = 0;
        int max = 0;

        while (i < dice.length) {
            if (max < dice[i]) {
                max = dice[i];
            }
            i++;
        }
        results = "Highest number is " + max + "!";
    }

    return results;

}

当它引用方法getCounts()时，它是以下代码：

private static int[] getCounts(int[] dice) {
    int[] count = new int[10];
    int i = 0;

    int one = 0;
    while (i < dice.length) {
        if (dice[i] == 1) {
            one++;
        }
        i++;
    }
    int two = 0;
    i = 0;
    while (i < dice.length) {
        if (dice[i] == 2) {
            two++;
        }
        i++;
    }
    int three = 0;
    i = 0;
    while (i < dice.length) {
        if (dice[i] == 3) {
            three++;
        }
        i++;
    }
    int four = 0;
    i = 0;
    while (i < dice.length) {
        if (dice[i] == 4) {
            four++;
        }
        i++;
    }
    int five = 0;
    i = 0;
    while (i < dice.length) {
        if (dice[i] == 5) {
            five++;
        }
        i++;
    }
    int six = 0;
    i = 0;
    while (i < dice.length) {
        if (dice[i] == 6) {
            six++;
        }
        i++;
    }
    int seven = 0;
    i = 0;
    while (i < dice.length) {
        if (dice[i] == 7) {
            seven++;
        }
        i++;
    }
    int eight = 0;
    i = 0;
    while (i < dice.length) {
        if (dice[i] == 8) {
            eight++;
        }
        i++;
    }
    int nine = 0;
    i = 0;
    while (i < dice.length) {
        if (dice[i] == 9) {
            nine++;
        }
        i++;
    }
    int ten = 0;
    i = 0;
    while (i < dice.length) {
        if (dice[i] == 10) {
            ten++;
        }
        i++;
    }

    count[0] = one;
    count[1] = two;
    count[2] = three;
    count[3] = four;
    count[4] = five;
    count[5] = six;
    count[6] = seven;
    count[7] = eight;
    count[8] = nine;
    count[9] = ten;

    return count;

}

Answer 1

首先尝试调试（使用实际的调试模式并放置断点或放置打印值）下面的代码部分。您的目标是在此代码块内的逻辑中找到裂痕。接下来尝试更新逻辑。

if (endResultsCheck < 6) {
    // Checks for full house
    i = 0;
    int check = 0;
    while (i < count.length) {
        if (count[i] == 3) {
            check++;
        }
        if (count[i] == 2) {
            check++;
        }
        i++;
    }
    if (check == 2) {
        results = "Full house!";
        endResultsCheck = 5;
    }
}

尝试先自己动手做。追寻失踪的和平很有趣。

当有两对时，

if (count[i] == 2) {条件将为真两次。结果，check == 2为真，您将收到“满屋”。

一种可能的解决方案：

if (endResultsCheck < 6) {
    // Checks for full house
    i = 0;
    boolean hasPair = false;
    boolean hasTriplet = false;
    while (i < count.length) {
        if (count[i] == 3) {
            hasTriplet = true;
        }
        if (count[i] == 2) {
            hasPair = true;
        }
        i++;
    }
    if (hasPair && hasTriplet) {
        results = "Full house!";
        endResultsCheck = 5;
    }
}

Java扑克骰子计划

1 个答案: