我真的可以真正地使用一些帮助。关于使用ASIFormDataRequest进行照片上传,我已经查看了一些详细的文档(对于傻瓜)。有人可以通过我这里的生命线吗?
虽然我知道我可能会离开,但这里有相关内容(相关部分)。
Camera.h
#import <UIKit/UIKit.h>
@class ASIFormDataRequest;
...
Camera.m
#import "Camera.h"
#import "ASIHTTPRequest.h"
#import "ASIFormDataRequest.h"
...
- (void)uploadImage:(NSData *)imageData filename:(NSString *)filename{
NSURL *url = [NSURL URLWithString:@"http://moosesightings.com/test.php"];
ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:url];
// Upload a file on disk
[request setData:imageData withFileName:filename andContentType:@"image/jpeg" forKey:@"userfile"];
[request setDelegate:self];
[request startAsynchronous];
}
...
- (void) imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info
{
[picker dismissModalViewControllerAnimated:YES];
[picker.view removeFromSuperview];
// Access the uncropped image from info dictionary
UIImage *image = [info objectForKey:@"UIImagePickerControllerOriginalImage"];
NSString *imageName = @"uploaded.jpg";
// Save image
//UIImageWriteToSavedPhotosAlbum(image, self, @selector(image:didFinishSavingWithError:contextInfo:), nil);
[self uploadImage:UIImageJPEGRepresentation(imageView.image, 1.0) filename:imageName];
captionControls.hidden = NO;
[textView becomeFirstResponder];
[picker release];
}
这是我收到的脚本。
$dir_dest = 'uploads/';
ob_start();
print_r($_FILES);
$test = ob_get_contents();
ob_end_clean();
$db->insert('connecttest', array('ts'=>date('Y-m-d H:i:s'), 'tempfield'=>$test))->execute();
以下是我得到的结果
Array
(
[(null)] => Array
(
[name] => (null)
[type] => (null)
[tmp_name] => C:\Windows\Temp\phpCFF0.tmp
[error] => 0
[size] => 0
)
)
请帮助:(
答案 0 :(得分:7)
我遇到了类似的问题,我使用
重新调整了图像大小UIImage *im = [info objectForKey:@"UIImagePickerControllerOriginalImage"] ;
UIGraphicsBeginImageContext(CGSizeMake(320,480));
[im drawInRect:CGRectMake(0, 0,320,480)];
newImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
NSData* imageData=UIImageJPEGRepresentation(newImage, 0.5);
它开始工作,捕获图像的高度和宽度将超过2000x2000,所以减少它并尝试。
[request setData:imageData withFileName:@"photo.jpg" andContentType:@"image/jpeg" forKey:@"file"];
这是php脚本。
$filename="uploaded";
$target_path = "uploads/";
$target_path = $target_path .$filename.".jpg";
if(move_uploaded_file($_FILES['file']['tmp_name'], $target_path)) {
echo "uploaded an image";
} else{
echo "There was an error uploading the file, please try again!";
}