Question

我正在使用Python根据键对字典项进行排序。但是输出没有给出适当的排序。有人可以帮忙吗？谢谢！这是我的代码：

{
label: 'Edit',
submenu: [
  {
    label: 'Compose',
    accelerator: 'CmdOrCtrl+N',
    click(menuItem, forcedWindow, options) {
      if (forcedWindow) {
        forcedWindow.webContents.sendInputEvent({type: 'keyUp', keyCode: 'c'});
      }
    }
  }
 ]
}

输出为：

expected_output= {'13':['0.0'], '14':['8.0'], '99':['1.0'], '100':['1.0'], 
'101':['0.0'], '102':['1.0'], '103':['1.0'], '104':['0.0'], '105':['0.0'], 
'106':['1.0'], '107':['1.0'], '108':['0.0'], '109':['0.0']}
expected_output=collections.OrderedDict(sorted(expected_output.items(), key=lambda t: t[1]))
print("Expected Output:")
print(expected_output)

Answer 1

items()返回(key, value)对。 t[1]正在查看该对的第二部分，即值。随便

expected_output=collections.OrderedDict(sorted(expected_output.items()))

这将给我们

OrderedDict([('100', ['1.0']), ('101', ['0.0']), ('102', ['1.0']), ('103', ['1.0']), 
             ('104', ['0.0']), ('105', ['0.0']), ('106', ['1.0']), ('107', ['1.0']), 
             ('108', ['0.0']), ('109', ['0.0']), ('13', ['0.0']), ('14', ['8.0']), ('99', ['1.0'])])

如果要对整数（而不是字符串）进行排序，则可以进行

expected_output=collections.OrderedDict(sorted(expected_output.items(), 
                                               key=lambda pair: int(pair[0])))

获得

OrderedDict([('13', ['0.0']), ('14', ['8.0']), ('99', ['1.0']), ('100', ['1.0']),
             ('101', ['0.0']), ('102', ['1.0']), ('103', ['1.0']), ('104', ['0.0']),    
             ('105', ['0.0']), ('106', ['1.0']), ('107', ['1.0']), ('108', ['0.0']), 
             ('109', ['0.0'])])

Python Dict排序问题

1 个答案: