Question

这是我的代码，可从单词列表中找到复杂的单词。

“ complex_words.py”

def complex_words_count(words_list):
    cw_count = 0
    vowels = ['a', 'e', 'i', 'o', 'u']
    for word in words_list:
        syl_count = 0
        for w in vowels:
            if w in word and word[-2:len(word)] != 'es | ed':
                syl_count+=1
        if syl_count > 2:
            cw_count+=1
    return cw_count

from Words_Count import word_count

def complex_words_percent():
    cwc = complex_words_count(words_list)
    wc = word_count(words_list)

    percent_cw = int(cwc/wc*100)

    return percent_cw

“ Words_Count.py”

def word_count(words_list):

    wc = len(words_list)

    return wc

“ Test.py”

from complex_words import complex_words_count, complex_words_percent

a = ['inferno', 'shamed', 'changes', 'umbrella']

cw_c = complex_words_count(a)

cw_p = complex_words_percent()

complex_words_count（）函数绝对可以正常工作，但问题出在complex_words_percent（）

Here's a screenshot representing the fault in the function

运行“ Test.py”时的输出：

Output of "Test.py"

我没有办法正确运行“ Test.py”。

Answer 1

您将单词列表a传递给了complex_words_count函数，但是complex_words_percent对此一无所知。您还必须将其作为该函数的参数添加：

def complex_words_percent(words_list):
    cwc = complex_words_count(words_list)
    wc = word_count(words_list)

    percent_cw = int(cwc/wc*100)

    return percent_cw

并在调用函数时将其传递：

cw_p = complex_words_percent(a)

如果要在函数之间共享值，则应将它们放在一个类中：

class ComplexWords:
    def __init__(self, words_list):
        self.words_list = words_list

    def count(self):
        words_list = self.words_list
        ... rest of code here ...

    def percent(self):
        words_list = self.words_list
        ... rest of code here ...

然后使用它：

cw = ComplexWords(a)
cw_c = cw.count()
cw_p = cw.percent()

Answer 2

编辑为“ complex_words.py”

w0 = []
def complex_words_count(words_list):
    global w0
    w0 = words_list
    cw_count = 0
    vowels = ['a', 'e', 'i', 'o', 'u']
    for word in words_list:
        syl_count = 0
        for w in vowels:    
            if w in word and word[-2:len(word)] != 'es | ed':
                syl_count+=1
        if syl_count > 2:
            cw_count+=1
    return cw_count

from Words_Count import word_count 

def complex_words_percent(words_list = None):
    if words_list is None:
        words_list = w0

    cwc = complex_words_count(w0)
    wc = word_count(w0)

    percent_cw = int(cwc/wc*100)

    return percent_cw

这给了我想要的“ Test.py”的确切输出

在函数内其他文件上调用函数时参数未定义

2 个答案: