Question

我有一个带有内部嵌套对象的json字符串，如下所示：

{
    "stringTypeCode": "aaaaa",
    "choiceTypeCode1": {
        "option1": true,
        "option2": true
    },
    "choiceTypeCode2": {
        "option3": true,
        "option4": true
    }
}

我需要将其转换为将嵌套对象保留为字符串的Map：

stringTypeCode - aaaaa
choiceTypeCode1 - {"option1": true,"option2": true}
choiceTypeCode2 - {"option2": true,"option3": true}

是否可以以简单的方式完成操作，最好没有任何库？

编辑：如果没有其他简单方法，则使用库。

Edit2：我在对象中具有可变数量的属性和变量名。

Answer 1

将json解析为映射或通用json结构，遍历$inputFileType = 'Csv'; $inputFileNames = [ './sampleData/example1.csv', './sampleData/example2.csv' './sampleData/example3.csv' ]; /** Create a new Reader of the type defined in $inputFileType **/ $reader = \PhpOffice\PhpSpreadsheet\IOFactory::createReader($inputFileType); /** Extract the first named file from the array list **/ $inputFileName = array_shift($inputFileNames); /** Load the initial file to the first worksheet in a `Spreadsheet` Object **/ $spreadsheet = $reader->load($inputFileName); /** Set the worksheet title (to the filename that we've loaded) **/ $spreadsheet->getActiveSheet() ->setTitle(pathinfo($inputFileName,PATHINFO_BASENAME)); /** Loop through all the remaining files in the list **/ foreach($inputFileNames as $sheet => $inputFileName) { /** Increment the worksheet index pointer for the Reader **/ $reader->setSheetIndex($sheet+1); /** Load the current file into a new worksheet in Spreadsheet **/ $reader->loadIntoExisting($inputFileName,$spreadsheet); /** Set the worksheet title (to the filename that we've loaded) **/ $spreadsheet->getActiveSheet() ->setTitle(pathinfo($inputFileName,PATHINFO_BASENAME)); }对，然后根据key - value对创建新映射。 key - toJsonString(value)可能是简单的字符串，json对象，数字等...

通过一个简单的Jackson ObjectMapper：

value

您的示例产生：

String json = "YOUR JSON HERE";
ObjectMapper mapper = new ObjectMapper();
Iterator<Entry<String, JsonNode>> fields = mapper.readTree(json).fields();
Map<String, String> m = new HashMap<>();
while (fields.hasNext()) {
    Entry<String, JsonNode> field = fields.next();
    m.put(field.getKey(), mapper.writeValueAsString(field.getValue()));
}
m.entrySet().forEach(e -> System.out.println(e.getKey() + " - " + e.getValue()));

带有嵌套对象的Json字符串到Map <string，string>

1 个答案: