Question

我想通过菜单创建一个计算器。

我输入第一个和第二个数字，然后选择是否要对两个数字进行加，减，除，乘，乘运算或乘以3或4。

也可以使用选项菜单和上下文菜单。这是我到目前为止所做的。

package com.example.asus.menuassignment;

import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.ContextMenu;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.EditText;
import android.widget.TextView;

public class MainActivity extends AppCompatActivity {


    EditText text1;
    EditText text2;
    TextView text;
    int fNum;
    int sNum;
    int result;
    @Override
    protected void onCreate(Bundle savedInstanceState)
    {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        text1 = (EditText)findViewById(R.id.editText);
        text2 = (EditText)findViewById(R.id.editText2);
        text = (TextView)findViewById(R.id.textView3);
        fNum = Integer.parseInt(text1.getText().toString());
        sNum = Integer.parseInt(text2.getText().toString());
        registerForContextMenu(text);

    }
//options menu part
    @Override
    public boolean onCreateOptionsMenu(Menu menu)
    {
        getMenuInflater().inflate(R.menu.menu, menu);
        return super.onCreateOptionsMenu(menu);
    }

    @Override
    public boolean onOptionsItemSelected(MenuItem item)
    {

        switch (item.getItemId())
        {
            //multiply

            case R.id.item1:
                result = fNum*sNum;
                text.setText(String.valueOf(result));
                return true;

            //multiplying a result by 3 or 4
            case R.id.item11:
                result = result * 3;
                text.setText(String.valueOf(result));
                return true;
            case R.id.item12:
                result = result * 4;
                text.setText(String.valueOf(result));
                return true;

                //Add
            case R.id.item2:
                result = fNum + sNum;
                text.setText(String.valueOf(result));
                return true;
                //Subtract
            case R.id.item3:
                result = fNum - sNum;
                text.setText(String.valueOf(result));
                return true;
                //Divide
            case R.id.item4:
                result = fNum / sNum;
                text.setText(String.valueOf(result));
                return true;


        }
        return super.onOptionsItemSelected(item);
    }
 //By long pressing the result a context menu appears
    @Override
    public void onCreateContextMenu(ContextMenu menu, View v, ContextMenu.ContextMenuInfo menuInfo)
    {
        getMenuInflater().inflate(R.menu.menu, menu);
        super.onCreateContextMenu(menu, v, menuInfo);
    }

    @Override
    public boolean onContextItemSelected(MenuItem item)
    {
        switch (item.getItemId()) {
            //multiply

            case R.id.item1:
                result = fNum * sNum;
                text.setText(String.valueOf(result));
                return true;

            //multiplying a result by 3 or 4
            case R.id.item11:
                result = result * 3;
                text.setText(String.valueOf(result));
                return true;
            case R.id.item12:
                result = result * 4;
                text.setText(String.valueOf(result));
                return true;

            //Add
            case R.id.item2:
                result = fNum + sNum;
                text.setText(String.valueOf(result));
                return true;
            //Subtract
            case R.id.item3:
                result = fNum - sNum;
                text.setText(String.valueOf(result));
                return true;
            //Divide
            case R.id.item4:
                result = fNum / sNum;
                text.setText(String.valueOf(result));
                return true;
        }

        return super.onContextItemSelected(item);
    }

}

我没有任何错误，但是应用程序崩溃了，究竟是什么错误或这里缺少什么？

更新：This is the logcat

Answer 1

该应用程序崩溃，原因是以下代码 fNum = Integer.parseInt（text1.getText（）。toString（））; sNum = Integer.parseInt（text2.getText（）。toString（））;

最初，textview中将没有任何值。从setContentView方法中删除这些行。在计算结果之前，将这些行添加到OnOptionsItemSelected函数中。

希望有帮助。

Answer 2

textview text1和text2的值为null，这就是它崩溃的原因删除onCreate上的初始化

    @Override
    protected void onCreate(Bundle savedInstanceState)
    {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        text1 = (EditText)findViewById(R.id.editText);
        text2 = (EditText)findViewById(R.id.editText2);
        text = (TextView)findViewById(R.id.textView3);        
        // fNum = Integer.parseInt(text1.getText().toString()); // remove this line        
        // sNum = Integer.parseInt(text2.getText().toString()); // remove this line
        registerForContextMenu(text);

    }

并且由于您声明fNum和sNum是全局变量。我们可以创建一个函数并从text1和text2

获取值

// Get the data from text view
private void getData() { 
   fNum = Integer.parseInt(text1.getText() + ""); 
   sNum = Integer.parseInt(text2.getText() + ""); 
}

在执行计算之前先调用它

@Override
public boolean onOptionsItemSelected(MenuItem item) {

    getData() // GET THE DATA

    switch (item.getItemId()) {
        case R.id.item1:
            result = fNum*sNum;
            text.setText(String.valueOf(result));
            return true;
        .
        .
        .
    }
    return super.onOptionsItemSelected(item);
}

以及此处：

@Override
public boolean onContextItemSelected(MenuItem item) {

    getData() // GET THE DATA

    switch (item.getItemId()) {
        case R.id.item1:
            result = fNum * sNum;
            text.setText(String.valueOf(result));
            return true;
        .
        .
        .
    return super.onContextItemSelected(item);
}

在Android中创建计算器菜单

2 个答案: