Question

我向API发送请求，并获得了JSON：

{{
  "id": 1,
  "name": "LoginTest",
  "status": "ready",
  "testvalues_count": 2,
  "testvalues": [
    {
      "id": 1,
      "name": "Username",
      "value": "Test"
    },
    {
      "id": 2,
      "name": "Password",
      "value": "password1"
    }
  ]
}}

我可以轻松获得name项的值：

var api = new DataApi();
var json = api.GetTestData("LoginTest");
dynamic testData = JsonConvert.DeserializeObject<dynamic>(json);
var name = testData.name;

但是我还需要Username和Password项目的值。我该怎么办？

Answer 1

您只需在VS Edit / Special paste菜单中粘贴JSON对象即可为json创建一个类

public class Rootobject
{
    public int id { get; set; }
    public string name { get; set; }
    public string status { get; set; }
    public int testvalues_count { get; set; }
    public Testvalue[] testvalues { get; set; }
}

public class Testvalue
{
    public int id { get; set; }
    public string name { get; set; }
    public string value { get; set; }
}

然后

Rootobject testData = JsonConvert.DeserializeObject<Rootobject>(json);

获取嵌套的JSON值

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